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首页> 外文期刊>Optical Materials >Bi~(3+) enhanced red emission in Sr_(0.5)Ca_(0.4)MoO_4:Eu~(3+) phosphor
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Bi~(3+) enhanced red emission in Sr_(0.5)Ca_(0.4)MoO_4:Eu~(3+) phosphor

机译:Bi〜(3+)增强Sr_(0.5)Ca_(0.4)MoO_4:Eu〜(3+)荧光粉的红色发射

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摘要

A series of Eu~(3+) single-doped Sr_(0.9-x)Ca_xMoO_4 and Bi~(3+)-Eu~(3+) co-doped Sr_(0.5)Ca_(0.4)MoO_4 red phosphors were prepared via a co-precipitation reaction. The X-ray diffraction patterns show that doping Bi~(3+) ions in Sr_(0.5)-Ca_(0.4)MoO_4Eu_(0.1~3) cause the host crystal orientation changed. The photoluminescent results show that the synthesized phosphor powders can be effectively excited at the wavelengths of 395 nm in ultraviolet light area and 464 nm in blue light area and 534 nm in green light area, and Strongly enhanced red emission of Eu~(3+)is obtained by adding Bi~(3+) instead of increasing the Eu~(3+) concentration. For a fixed Eu~(3+) concentration, there is an optimal Bi~(3+) concentration, at which the maximum luminescence intensity is achieved. The proposed explanation of these changes can not only be attributed to the energy transfer between Bi~(3+) and Eu~(3+) but also to the change in the symmetry of Eu~(3+) ions when doping Bi~(3+) into Sr_(0.5)Ca_(0.4)MoO_4Eu_(0.1)~3.
机译:制备了一系列Eu〜(3+)单掺杂Sr_(0.9-x)Ca_xMoO_4和Bi〜(3 +)-Eu〜(3+)共掺杂Sr_(0.5)Ca_(0.4)MoO_4红色荧光粉。共沉淀反应。 X射线衍射图谱表明,在Sr_(0.5)-Ca_(0.4)MoO_4Eu_(0.1〜3)中掺杂Bi〜(3+)离子会导致基质晶体取向发生变化。光致发光结果表明,所合成的荧光粉在紫外光区395 nm,蓝光区464 nm,绿光区534 nm的波长下均能有效激发,并强烈增强Eu〜(3+)的红色发射。通过添加Bi〜(3+)而不是增加Eu〜(3+)的浓度来获得Cd。对于固定的Eu〜(3+)浓度,存在最佳的Bi〜(3+)浓度,在该浓度下可获得最大的发光强度。提出的这些变化的解释不仅可以归因于Bi〜(3+)与Eu〜(3+)之间的能量转移,还可以归因于掺杂Bi〜(3+)时Eu〜(3+)离子的对称性变化。 3+)变成Sr_(0.5)Ca_(0.4)MoO_4Eu_(0.1)〜3。

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