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One-radius results for supermedian functions on mathbb Rd{mathbb R^d} , d ≤ 2

机译:Mathbb R d {mathbb R ^ d}上的中值函数的一半径结果,d≤2

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A classical result states that every lower bounded superharmonic function on is constant. In this paper the following (stronger) one-circle version is proven. If is lower semicontinuous, lim inf|x|→∞ f (x)/ ln |x| ≥ 0, and, for every , , where is continuous, src="/content/RW4175UQ77556523/208_2010_488_Article_IEq7.gif" alt="$${{rm sup}_{x in mathbb{R}^{2}} (r(x) - |x|) , and , then f is constant. Moreover, it is shown that, assuming r ≤ c| · | + M on , d ≤ 2, and taking averages on , such a result of Liouville type holds for supermedian functions if and only if c ≤ c 0, where c 0 = 1, if d = 2, whereas 2.50 < c 0 < 2.51, if d = 1.
机译:一个经典的结果表明,每一个下界超谐波函数都是恒定的。本文证明了以下(更强)的单圆版本。如果为下半连续,则lim inf | x |→∞ f(x)/ ln | x | ≥0,并且对于每个连续的, src =“ / content / RW4175UQ77556523 / 208_2010_488_Article_IEq7.gif” alt =“ $$ {{rm sup} _ {x in mathbb {R} ^ {2}} (r(x)-| x |),则f为常数,此外,证明当r≤c |·| + M on,d≤2并取平均值时,Liouville的结果当且仅当c≤c 0 ,其中c 0 = 1,如果d = 2,而2.50 0 <2.51,如果d = 1。

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