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ON EIGENFUNCTIONS OF THE FOURIER TRANSFORM

机译:关于傅立叶变换的本征函数

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摘要

A nontrivial example of an eigenfunction in the sense of the theory of distributions for the planar Fourier transform was described by the authors in their previous work. In this paper, a method for obtaining other eigenfunctions is proposed. Positive homogeneous distributions in ℝ_( n )of order − n /2 are considered, and it is shown that F ( ω )| x |_(− n /2), | ω | = 1, is an eigenfunction in the sense of the theory of distributions of the Fourier transform if and only if F ( ω ) is an eigenfunction of a certain singular integral operator on the unit sphere of ℝ_( n ). Since Y m , n k ω x − n / 2 $$ {Y}_{m,n}^{(k)}left(omega right){left|mathbf{x}right|}^{-n/2} $$ , where Y m , n k $$ {Y}_{m,n}^{(k)} $$ denote the spherical functions of order m in ℝ_( n ), are eigenfunctions of the Fourier transform, it follows that Y m , n k $$ {Y}_{m,n}^{(k)} $$ are eigenfunctions of the above-mentioned singular integral operator. In the planar case, all eigenfunctions of the Fourier transform of the form F ( ω )| x |_(−1)are described by means of the Fourier coefficients of F ( ω ).
机译:作者在先前的工作中描述了在平面傅立叶变换的分布理论上本征函数的一个非平凡的例子。本文提出了一种获取其他特征函数的方法。考虑到阶数为−n / 2的ℝ_(n)的正均匀分布,表明F(ω)|。 x | _(− n / 2),| ω|当且仅当F(ω)是ℝ_(n)单位球面上某个奇异积分算子的本征函数时,从傅立叶变换的分布理论上讲,= 1是本征函数。由于Y m,nkωx − n / 2 $$ {Y} _ {m,n} ^ {(k)}左(Ω右){left | mathbf {x}右|} ^ {-n / 2} $$,其中Y m,nk $$ {Y} _ {m,n} ^ {(k)} $$表示ℝ_(n)中阶m的球面函数,是傅里叶变换的本征函数,因此Y m,nk $$ {Y} _ {m,n} ^ {(k)} $$是上述奇异积分算子的本征函数。在平面情况下,形式为F(ω)|的傅立叶变换的所有本征函数x | _(-1)通过F(ω)的傅立叶系数来描述。

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