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Abelian groups yield many large families for the diamond problem

机译:阿贝尔族人为钻石问题生出许多大家族

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摘要

There is much recent interest in excluded subposets. Given a fixed poset (P), how many subsets of ([n]) can be found without a copy of (P) realized by the subset relation? The hardest and most intensely investigated problem of this kind is when (P) is a diamond, i.e. the power set of a two-element set. In this paper, we show infinitely many asymptotically tight constructions using random set families defined from posets based on Abelian groups. They are provided by the convergence of Markov chains on groups. Such constructions suggest that the diamond problem is hard.
机译:最近人们对排除的子代产生了浓厚的兴趣。给定一个固定的姿态(P),在没有通过子集关系实现的(P)副本的情况下,可以找到([n])的多少子集?此类问题中最难且最深入研究的问题是(P)是钻石时,即两元素组的幂集。在本文中,我们使用从基于Abelian族的坐姿定义的随机集族来显示无限多个渐近紧构造。它们是通过马尔可夫链在组上的收敛来提供的。这样的结构表明钻石问题很难解决。

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