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A Faster Approximation Algorithm for the Gibbs Partition Function

机译:GIBBS分区功能的逼近算法

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We consider the problem of estimating the partition function $Z(eta)=sum_x exp(-eta H(x))$ of a Gibbs distribution with a Hamilton $H(cdot)$, or more precisely the logarithm of the ratio $q=ln Z(0)/Z(eta)$. It has been recently shown how to approximate $q$ with high probability assuming the existence of an oracle that produces samples from the Gibbs distribution for a given parameter value in $[0,eta]$. The current best known approach due to Huber (2015) uses $O(qln ncdot[ln q + ln ln n+arepsilon^{-2}])$ oracle calls on average where $arepsilon$ is the desired accuracy of approximation and $H(cdot)$ is assumed to lie in ${0}cup[1,n]$. We improve the complexity to $O(qln ncdotarepsilon^{-2})$ oracle calls. We also show that the same complexity can be achieved if exact oracles are replaced with approximate sampling oracles that are within $O(rac{arepsilon^2}{qln n})$ variation distance from exact oracles. Finally, we prove a lower bound of $Omega(qcdot arepsilon^{-2})$ oracle calls under a natural model of computation.
机译:我们考虑估计分区函数$ z( beta)= sum_x exp( - beta h(x))$与汉密尔顿$ h( cdot)$的gibbs分布,或更准确地对数比率$ q = ln z(0​​)/ z( beta)$。最近展示了如何近似$ Q $,假设存在从GIBBS分发中产生样本的Oracle,以便在$ [0, beta] $中生成了来自GIBBS分发的样本。由于Huber(2015)而使用$ O(Q ln n cdot [ ln q + ln ln n + varepsilon ^ { - 2}])呼叫平均而导致的最佳已知的方法是近似的所需准确性,假设$ h( cdot)$ in $ {0 } cup [1,n] $。我们将复杂性提高到$ O(Q ln n cdot varepsilon ^ { - 2})$ Oracle呼叫。我们还表明,如果以$ o( frac { varepsilon ^ 2} {q ln n})的近似采样oracelles替换了精确的orcacles,则可以实现相同的复杂性。从精确的oracles的$变化距离。最后,我们证明了$ omega的下限(q cdot varepsilon ^ { - 2})$ Oracle调用在计算的自然模型下。

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