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On the Largest Integer that is not a Sum of Distinct Positive nth Powers

机译:关于不是正n次幂的和的最大整数

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It is known that for an arbitrary positive integer n the sequence S(xn) = (1n, 2n, ...) is complete, meaning that every sufficiently large integer is a sum of distinct nth powers of positive integers. We prove that every integer         m ≥ (b - 1)2n-1(r + (2/3)(b - 1)(22n - 1) + 2(b - 2))n - 2a + ab, where a = n!2n2, b= 2n3an-1, r = 2n2 - na, is a sum of distinct positive nth powers.
机译:已知对于任意正整数n而言,序列S(xn)=(1n,2n,...)是完整的,这意味着每个足够大的整数都是正整数的不同n次幂的总和。我们证明每个整数m≥(b-1)2n-1(r +(2/3)(b-1)(22n-1)+ 2(b-2))n-2a + ab,其中a = n!2n2,b = 2n3an-1,r = 2n2-na,是不同的第n个幂的和。

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