Let G be a finite group, np(G) be the number of Sylow p??subgroup of G and t(2;G) be the maximal number of vertices in cocliques of the prime graph of G containing 2. In this paper we prove that if G is a centerless group with t(2;G) 2 and np(G)=np(S) f
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机译：令G为一个有限群，np（G）为G的Sylow p ??子群的个数，t（2; G）为G包含2的G的本图的共小群中的最大顶点数。证明如果G是t（2; G）2且np（G）= np（S）f
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