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Kappa statistic to measure agreement beyond chance in free-response assessments

机译:Kappa统计量,用于在自由响应评估中超出偶然性地衡量一致性

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Background The usual kappa statistic requires that all observations be enumerated. However, in free-response assessments, only positive (or abnormal) findings are notified, but negative (or normal) findings are not. This situation occurs frequently in imaging or other diagnostic studies. We propose here a kappa statistic that is suitable for free-response assessments. Method We derived the equivalent of Cohen’s kappa statistic for two raters under the assumption that the number of possible findings for any given patient is very large, as well as a formula for sampling variance that is applicable to independent observations (for clustered observations, a bootstrap procedure is proposed). The proposed statistic was applied to a real-life dataset, and compared with the common practice of collapsing observations within a finite number of regions of interest. Results The free-response kappa is computed from the total numbers of discordant ( b and c ) and concordant positive ( d ) observations made in all patients, as 2 d /( b + c +?2 d ). In 84 full-body magnetic resonance imaging procedures in children that were evaluated by 2 independent raters, the free-response kappa statistic was 0.820. Aggregation of results within regions of interest resulted in overestimation of agreement beyond chance. Conclusions The free-response kappa provides an estimate of agreement beyond chance in situations where only positive findings are reported by raters.
机译:背景技术通常的kappa统计信息要求列举所有观察值。但是,在自由响应评估中,只会通知阳性(或异常)发现,而不会通知阴性(或正常)发现。这种情况在成像或其他诊断研究中经常发生。我们在这里提出适用于自由响应评估的kappa统计量。方法我们在假设任何给定患者的可能发现数量非常大的假设下得出了两个评估者的Cohen kappa统计量的等值,以及适用于独立观察的抽样方差公式(对于聚类观察,自举程序)。拟议的统计数据已应用于实际数据集,并与在有限数量的感兴趣区域内折叠观测的常规做法进行了比较。结果由所有患者的不一致(b和c)和一致阳性(d)观察值的总数计算出自由反应kappa为2 d /(b + c +?2 d)。在由2位独立评估者评估的84例儿童全身磁共振成像程序中,自由应答kappa统计量为0.820。在感兴趣区域内的结果汇总导致对协议的高估是偶然的。结论在评估者仅报告积极发现的情况下,自由响应的Kappa可以提供对偶然性的一致估计。

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