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Built-in self test design of power switch with clock-gated charge/discharge transistor

机译:具有时钟门控充放电晶体管的电源开关的内置自检设计

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摘要

It is becoming common to implement header (footer) power switches in low-power system-on-chip. However, the switches are not tested for manufacturing defects in most designs currently. In this study, a novel built-in self test (BIST) solution for power switch is proposed. To accelerate the test of the header (footer) switches, a charge (discharge) transistor is adopted in the proposed BIST circuit and the corresponding charge (discharge) transistor is gated by the test clock. Therefore the number of test patterns, the length of test vectors and the test time are all decreased. Besides, the test responses can be identified easily. If the test responses are all logic-high, the tested switches are fault-free. Or else, the tested switches are faulty. In addition, the structure of the proposed BIST circuit can be scaled freely with the amount of switches. For m switches, it takes m + 2 cycles to locate the faulty switches at worst. Finally, to verify the proposed BIST circuit, the BIST design with 255 header switches is implemented with SMIC 0.18 ;C;m 1P6M logic process. The corresponding area is 0.043 mm2. The simulation results show that the BIST circuit can locate the possible manufacturing defects in the switches and discharge transistors within 257 clock cycles. The corresponding consumed power is 2.04 mW when the test frequency is 20 MHz.
机译:在低功耗片上系统中实现页眉(页脚)电源开关已变得越来越普遍。但是,目前在大多数设计中都未对开关进行制造缺陷测试。在这项研究中,提出了一种新颖的内置自检(BIST)电源开关解决方案。为了加速头(尾)开关的测试,在所提出的BIST电路中采用了充电(放电)晶体管,并且相应的充电(放电)晶体管由测试时钟选通。因此,测试图案的数量,测试向量的长度和测试时间都减少了。此外,可以轻松识别测试响应。如果测试响应均为逻辑高电平,则表明被测开关无故障。否则,测试的开关有故障。另外,所提出的BIST电路的结构可以随开关数量自由缩放。对于m个开关,最坏情况下需要花费m + 2个周期来定位故障开关。最后,为了验证提出的BIST电路,采用SMIC 0.18; C; m 1P6M逻辑过程实现了具有255个头开关的BIST设计。对应的面积为0.043 mm 2 。仿真结果表明,BIST电路可以在257个时钟周期内找到开关和放电晶体管中可能的制造缺陷。当测试频率为20 MHz时,相应的功耗为2.04 mW。

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