首页> 美国卫生研究院文献>Acta Crystallographica Section E: Crystallographic Communications >(Glycol-κ2 OO′)nitros­yl(η5-penta­methyl­cyclo­penta­dien­yl)ruthenium(II) bis­(tri­fluoro­methane­sulfonate)
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(Glycol-κ2 OO′)nitros­yl(η5-penta­methyl­cyclo­penta­dien­yl)ruthenium(II) bis­(tri­fluoro­methane­sulfonate)

机译:(乙二醇-κ2 OO)亚硝酰基(η5-五甲基环戊二烯基)钌(II)双(三氟甲磺酸盐)

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摘要

The title compound, [Ru(C10H15)(NO)(HOCH2CH2OH)](CF3SO3)2, possesses a three-legged piano-stool geometry around the Ru atom, with an average Ru—O distance of 2.120 (6) Å and an Ru—N—O angle of 159.45 (14)°. The ethyl­eneglycol ligand forms a non-planar metallacyclic ring by chelating the Ru atom via the O atoms. The O⋯O distances of 2.554 (2) and 2.568 (2) Å are indicative of hydrogen bonding between coordinated ethyl­eneglycol and outer-sphere trifluoro­methane­sulfonate fragments. The crystal packing is stabilized by ionic forces and several CH3⋯·F (2.585 and 2.640 Å) and CH3⋯O inter­actions (2.391, 2.678, 2.694 and 2.699 Å) between the penta­methyl­cyclo­penta­dienyl ligand and trifluoro­methane­sulfonate anion. There is noticeable short inter­molecular contact [2.9039 (16) Å], between an O atom of the SO3 group and a C atom of the penta­methyl­cyclo­penta­dienyl ligand.
机译:标题化合物[Ru(C10H15)(NO)(HOCH2CH2OH)](CF3SO3)2具有围绕Ru原子的三足钢琴凳几何形状,平均Ru-O距离为2.120(6)Å,并且Ru-N-O角为159.45(14)°。乙基乙二醇配体通过经由O原子螯合Ru原子形成非平面的金属环。 2.554(2)和2.568(2)的O⋯O距离指示配位的乙二醇与外球三氟­甲烷fragments磺酸盐碎片之间的氢键。晶体填充通过离子力和五­甲基­环戊­二烯基配体与三氟­甲烷­磺酸根阴离子之间的几个CH3⋯F(2.585和2.640Å)和CH3⋯O相互作用(2.391、2.678、2.6694和2.699Å)稳定。在SO 3基的O原子和五甲基­环戊­二烯基配体的C原子之间存在明显的短分子间接触[2.9039(16)]。

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