【2h】

Dualizing the Poisson summation formula.

机译:对偶泊松求和公式。

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摘要

If f(x) and g(x) are a Fourier cosine transform pair, then the Poisson summation formula can be written as 2sumfrominfinityn = 1g(n) + g(0) = 2sumfrominfinityn = 1f(n) + f(0). The concepts of linear transformation theory lead to the following dual of this classical relation. Let phi(x) and gamma(x) = phi(1/x)/x have absolutely convergent integrals over the positive real line. Let F(x) = sumfrominfinityn = 1phi(n/x)/x - integralinfinity0phi(t)dt and G(x) = sumfrominfinityn = 1gamma (n/x)/x - integralinfinity0 gamma(t)dt. Then F(x) and G(x) are a Fourier cosine transform pair. We term F(x) the "discrepancy" of phi because it is the error in estimating the integral phi of by its Riemann sum with the constant mesh spacing 1/x.
机译:如果f(x)和g(x)是傅立叶余弦变换对,则泊松求和公式可写为2sumfrominfinityn = 1g(n)+ g(0)= 2sumfrominfinityn = 1f(n)+ f(0)。线性变换理论的概念导致了这种经典关系的以下双重性。令phi(x)和gamma(x)= phi(1 / x)/ x在正实线上具有绝对收敛的积分。令F(x)= sumfrominfinityn = 1phi(n / x)/ x-积分infinity0phi(t)dt和G(x)= sumfrominfinityn = 1gamma(n / x)/ x-积分infinity0 gamma(t)dt。那么F(x)和G(x)是傅立叶余弦变换对。我们将F(x)称为phi的“离散度”,因为它是在常数网格间距为1 / x的情况下通过Riemann和估算积分phi的误差。

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