通过高温固相反应合成了La1/3 NbO3∶Sm3+荧光粉.样品的荧光光谱表明,La1/3NbO3∶Sm3+荧光粉最强的激发带在406 nm,对应于Sm3+的6H5/2→4K11/2跃迁,属于近紫外区(365 ～410 nm).当激发波长为406 nm时,样品的最强发射峰位于596 nm,是由Sm3+的4G5/2→6H7/2跃迁而产生的.因此,La1/3NbO3∶Sm3+可以作为基于近紫外激发的白光发光二极管(LED)的红光材料.而且,La位共掺杂Sr2+,Ba2+和Bi3+使样品的荧光强度大大增加,在最佳掺杂浓度时的量子产率分别为5.4％,7.5％和5.3％.%La1/3NbO3: Sm3+ phosphor was synthesized by solid state reaction at high temperature and its photoluminescence properties were investigated. Its strongest excitation band is at 406 nm, ascribed to 6H5/2→ 4K11/2 transition of Sm3+ in the range of near-ultraviolet region (NUV, 365-410 nm). And its strongest emission peak is at 596 nm, attributed to 4G5/2→ 6H7/2 transition of Sm3+. As a result, La1/3NbO3: Sm3+ phosphor shows great potential for future application as alternative red-emitting NUV-based white LEDs. The luminescence intensity can be strongly enhanced by codoping cation in the La-site, namely Sr2+, Ba2+and Bi3+. And the quantum yield is 5. 4% , 7. 5% and 5. 3% for Sr2+, Ba2+ and Bi3+ codoped samples respectively with the optimum doping concentration.
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