The present work devotes to the energy levels of positron under molecules XH (X = O, S, Se and Te) and the relations with nuclear field using Dirac equation based on the full symmetry group. Under these nuclear fields, the energy of positron is about e+ = - 1. 022 MeV. For the lower energy level, the energy of positron is increased with nuclear field; for the higher energy level, the energy of positron is nearly invariant with nuclear field. In this case, it is the three-photon annihilation. The formation of the positronium is in orthopositronium 3S, excited state, followed the conservation of charge parity.%基于全对称群的Dirac方程,研究当存在核场时的正电子能级及其与核场的关系,即计算在分子OH,SH,SeH和TeH的核场下的正电子能级.这时正电子的能量约为e+=-1.022 MeV.对于低能级,当核场强增大时,其能量有所升高,而对较高能级,核场强增大时,其能量无明显变化.正负电子的湮没过程为三光子湮没过程(the three-photo annihilation).而当生成e+-e-束缚系统,即正电子原子(positronium)时,为3S态,即正态的正电子原子(orthopositronium),为激发态,这是由电荷宇称守恒所确定的.
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