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Nonenzymatic mechanisms of oxidation/reduction reactions of biologically important organic compounds.

机译:生物学上重要的有机化合物的氧化/还原反应的非酶机制。

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摘要

Ascorbate acid, 2,3-dimethyl-1,4-hydroquinone and the vitamin E analogue Trolox normally oxidize by losing hydrogen atoms rather than electrons. Imidazole promotes oxidation of these compounds as assessed by cyclic voltammetry at pH 8.0. In the presence of a high concentration of imidazole, the oxidizing peaks of all three compounds are shifted toward lower potentials. By contrast, imidazole does not affect the cyclic voltammogram of methyl viologen, which undergoes electron rather than hydrogen-atom transfer. Imidazole is effective at pH 8.0 but only to a lesser extent at pH 5.5 indicating that it is the unprotonated form of imidazole that facilitates oxidation.;Imidazole and histamine also increase the rate of oxygen reduction by the biological organic reductants. Cyclic voltammogram data shows that imidazole and histamine affect the reductants rather than the potential of O2/O 2-·. This effect depends on the pH and concentration of imidazole or histamine. These results are consistent with the organic redox complex mechanism.;Dopamine oxidizes to an o-quinone especially at high pH. The dopamine side chain then inserts into the catechol ring forming a bicyclic compound, dopaminochrome. 4-Methylcatechol, a dopamine analogue that lacks the side-chain amine required for cyclization was studied. 4-Methylcatechol oxidizes in solution and adds H2O to form 4-methyl-1,2,5-trihydroxybenzene. This consumes O2 but is not inhibited by superoxide dismutase. Because the reduction potential of 4-methylcatechol is too high to reduce O2 to superoxide, O2 is most likely reduced by the 4-methylcatechol semiquinone formed by comproportionation of methylcatechol and the methylcatechol quinone. Aniline reacts quickly with the 4-methylcatechol quinone, eliminating it and halting formation of the semiquinone by comproportionation. Thus, methylcatechol oxidation in the presence of aniline requires superoxide. Superoxide is probably generated by reaction of the methylcatechol-aniline adduct with O2. These results suggest that cyclization of the dopamine quinone prevents the formation of other products such as 6-hydroxydopamine, the adduct formed by H2 O addition, and also the comproportionation of dopamine, which would facilitate oxidation.
机译:抗坏血酸,2,3-二甲基-1,4-氢醌和维生素E类似物Trolox通常通过失去氢原子而不是电子来氧化。通过循环伏安法在pH 8.0评估,咪唑可促进这些化合物的氧化。在高浓度的咪唑存在下,所有三种化合物的氧化峰都移向较低的电位。相反,咪唑不影响甲基紫精的循环伏安图,甲基紫精经电子而不是氢原子转移。咪唑在pH 8.0时有效,但在pH 5.5时作用较小,表明咪唑的未质子化形式有助于氧化。咪唑和组胺还可以提高生物有机还原剂的氧还原速率。循环伏安图数据表明,咪唑和组胺影响还原剂,而不是O2 / O 2-·的潜力。该作用取决于pH和咪唑或组胺的浓度。这些结果与有机氧化还原络合物的机理是一致的。多巴胺被氧化成邻醌,尤其是在高pH下。然后,多巴胺侧链插入邻苯二酚环中,形成双环化合物多巴胺色素。研究了4-甲基邻苯二酚,一种多巴胺类似物,它缺乏环化所需的侧链胺。 4-甲基邻苯二酚在溶液中氧化并添加H2O以形成4-甲基-1,2,5-三羟基苯。这会消耗氧气,但不会被超氧化物歧化酶抑制。由于4-甲基邻苯二酚的还原电位过高而无法将O2还原为超氧化物,因此O2最有可能被甲基邻苯二酚和甲基邻苯二酚醌的比例化形成的4-甲基邻苯二酚半醌还原。苯胺与4-甲基邻苯二酚醌快速反应,消除了苯胺,并通过相称作用阻止了半醌的形成。因此,在苯胺存在下的甲基邻苯二酚氧化需要超氧化物。超氧化物可能是由甲基邻苯二酚-苯胺加合物与O2反应生成的。这些结果表明,多巴胺醌的环化阻止了其他产物的形成,例如6-羟基多巴胺,通过添加H 2 O而形成的加合物以及多巴胺的共歧化,这将促进氧化。

著录项

  • 作者

    Li, Guoliang.;

  • 作者单位

    Wayne State University.;

  • 授予单位 Wayne State University.;
  • 学科 Chemistry Biochemistry.
  • 学位 Ph.D.
  • 年度 2007
  • 页码 95 p.
  • 总页数 95
  • 原文格式 PDF
  • 正文语种 eng
  • 中图分类
  • 关键词

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