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Edge-Simple Circuits through 10 Ordered Vertices in Square Grids

机译:边缘简单电路通过10个排序的顶点在方形网格中

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A circuit in a simple undirected graph G - (V, E) is a sequence of vertices {v_1, v_2, ..., v_(k+1)} such that v_1 = v_(k+1) and {v_i, v_(i+i) ∈ E for i = 1, ..., k. A circuit C is said to be edge-simple if no edge of G is used twice in C. In this article we study the following problem: which is the largest integer k such that, given any subset of k ordered vertices of an infinite square grid, there exists an edge-simple circuit visiting the k vertices in the prescribed order? We prove that k = 10. To this end, we first provide a counterexample implying that k < 11. To show that k ≥ 10, we introduce a methodology, based on the notion of core graph, to reduce drastically the number of possible vertex configurations, and then we test each one of the resulting configurations with an ILP solver.
机译:一个简单的无向图G - (v,e)的电路是一系列顶点{v_1,v_2,...,v_(k + 1)},使得v_1 = v_(k + 1)和{v_i,v_ (i + i)∈ei = 1,...,k。如果在C中使用两次,则据说电路C是简单的 - 简单。在C中没有两次使用。在本文中,我们研究以下问题:这是最大的整数k,使得无限广场的k有序顶点的任何子集。网格,存在一个边缘简单的电路,以规定的顺序访问K顶点?我们证明了k = 10.在此目的,我们首先提供一个暗示k <11.要显示k≥10,我们介绍了一种基于核心图的概念的方法,以急剧减少可能的顶点的数量配置,然后使用ILP求解器测试所产生的配置之一。

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