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ROUTING WITH MINIMUM NUMBER OF LANDMARKS

机译:使用最少数量的地标路由

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摘要

Routing problem has been studied for decades. In this paper, we focus on one of the routing problems: finding a path from source to destination on road network with the guidance of landmarks. People use landmarks to identify previously visited places and reoriented themselves in the environment. When people give direction instructions for other people, they also like to refer to landmarks. In this sense, we want to find a path such that it visits as many landmarks as possible but also the distance of the path is as short as possible. However, in some situations, the wayfinder may not want to see as many landmarks as possible along the way. For example, the wayfinder drives a car from source to destination. He probably doesn't want to use many landmarks to guide his driving since it's not convenient to switch from one landmark to the other landmark frequently. But he still want to have at least one landmark to be seen at any point along the way. Therefore, the problem becomes: find a path P from s to t such that the driver can see at least one landmark at any point along P and the number of landmarks the driver can stick to is minimized. There are two cases: (a) The same landmark in different road segments counts twice. (b) The same landmark in different road segments counts once. We give the optimal solutions for those two problems by using modified Dijkstra's shortest path algorithm and modified Bellman-Ford algorithm.
机译:已经研究了路由问题几十年。在本文中,我们专注于一个路由问题:在道路网络上找到从地标的路径到目的地的路径。人们使用地标来识别以前访问过的地方,并在环境中重新定位。当人们向其他人提供方向指示时,他们也想参考地标。从这个意义上讲,我们想找到一条路径,使得它可以尽可能多地访问,但是路径的距离尽可能短。然而,在某些情况下,Wayfinder可能不希望尽可能多地看到尽可能多的地标。例如,Wayfinder驱动从源到目的地的汽车。他可能不想使用许多地标来指导他的驾驶,因为它不方便地从一个地标经常切换到其他地标。但他仍然希望在途中至少看到一个地标。因此,问题变为:从S到T的路径p,使得驾驶员可以在沿着P的任何点处看到至少一个地标,并且驾驶员可以坚持最小化的地标数。有两种情况:(a)不同路段中的相同地标计数两次。 (b)不同的道路段中的相同地标计数一次。我们通过使用修改的Dijkstra的最短路径算法和改进的Bellman-Ford算法来提供这两个问题的最佳解决方案。

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