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The Multiple Traveling Salesman Problem on Spiders

机译:蜘蛛上的多个旅行推销员问题

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摘要

Given (ⅰ) a set of N + 1 vertices, that corresponds to N clients and 1 depot, (ⅱ) the travel time between each pair of vertices and (ⅲ) a number m of salespersons, the multiple traveling salesman problem consists in finding m tours such that, starting from the depot, all clients are visited in such a way that some objective function is minimized. The objective function we consider in this paper is the makespan. More precisely, the goal is to find m tours (one for each salesperson) that minimize the time elapsed from the beginning of the operation until the last salesman comes back to the depot. We take into account handling times, i.e., the time spent visiting each client, which we assume to be the same for all of them. We address the problem in the particular case where the depot-clients network is a spider, with the depot located at its center. We show that this case is NP-hard even for 2 salespersons. We also show structural properties of the optimal solutions. These properties allow us to devise a PTAS for minimizing the makespan. More precisely, a (1 + ε)-approximation algorithm with running time N~(O(m/ε)).
机译:给定(Ⅰ)一组N + 1顶点,它对应于N个客户端和1仓库,(Ⅱ)每对顶点和(Ⅲ)的行程时间和(Ⅲ)的销售人员,多次旅行推销员问题在于寻找M巡视使得从仓库开始,所有客户端都被访问,使得一些客观函数最小化。我们在本文中考虑的目标函数是Makespan。更确切地说,目标是找到最小化操作开始前一开始的时间的M Tours(每个销售人员),直到最后一次推销员回到仓库之前。我们考虑到处理时间,即,访问每个客户的时间,我们认为对所有客户来说都是相同的。我们在仓库 - 客户网络是蜘蛛的特定情况下解决了问题,该仓库位于其中心。我们表明,即使是2个销售人员,也表明这种情况是NP - 努力。我们还显示了最佳解决方案的结构性。这些属性允许我们设计用于最小化Makespan的PTA。更确切地说,具有运行时间n〜(O(m /ε))的(1 +ε)千克估计算法。

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