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Reducing 3SUM to Convolution-3SUM

机译:减少3升卷积-3sum

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Given a set S of n numbers, the 3SUM problem asks to determine whether there exist three elements a, b, c ∈ S such that a + b + c = 0. The related Convolution-3SUM problem asks to determine whether there exist a pair of indices i, j such that A[i] + A[j] = A[i + j], where A is a given array of n numbers. When the numbers are integers, a randomized reduction from 3SUM to Convolution-3SUM was given in a seminal paper by Patrascu [STOC 2010], which was later improved by Kopelowitz, Pettie, and Porat [SODA 2016] with an O(log n) factor slowdown. In this paper, we present a simple deterministic reduction from 3SUM to Convolution-3SUM for integers bounded by U. We also describe additional ideas to obtaining further improved reductions, with only a (log log n)~(O(1)) factor slowdown in the randomized case, and a log~(O(1)) U factor slowdown in the deterministic case.
机译:给定N个数字的组,3SUM问题要求确定是否存在三个元素A,B,C∈S,使得+ B + C = 0.相关的卷积-3Sum问题要求确定是否存在一对 索引I,j使得[i] + a [j] = a [i + j],其中a是一个给定的n个数组。 当这些数字是整数时,通过Patrascu [STOC 2010]在一个精细纸上给出了从3Sum到卷积-3Sum的随机减少,后来被Kopelowitz,Pettie和Porat [Soda 2016]改善了一个O(log n) 因子放缓。 在本文中,我们向由U的整数提出了从3Sum到卷积-3Sum的简单确定性减少。我们还描述了额外的想法,以获得进一步改进的缩减,只有一个(日志log n)〜(o(1))因子减速 在随机案例中,和一个日志〜(O(1))U因子在确定性情况下放缓。

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