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In vivo N-acetyl cysteine reduce hepatocyte death by induced acetaminophen

机译:体内N-乙酰半胱氨酸通过诱导乙酰氨基酚减少肝细胞死亡

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Acetaminophen (APAP) is the famous drug in global, and taking overdose Acetaminophen will intake hepatic cell injure. Desptie substantial progress in our understanding of the mechanism of hepatocellular injury during the last 40 years, many aspects of the pathophysiology are still unknown or controversial.1 In this study, mice are injected APAP overdose to damage hepatocyte. APAP deplete glutathione and ATP of cell, N-Acetyl Cysteine (NAC) plays an important role to protect hepatocytes be injury. N-Acetyl Cysteine provides mitochondrial to produce glutathione to release drug effect hepatocyte. By 6-carboxyfluorescein diacetate (6-CFDA) metabolism in vivo, glutathione keep depleting to observe the hepatocyte morphology in time. Without NAC, cell necrosis increase to plasma membrane damage to release 6-CFDA, that's rupture. After 6-CFDA injection, fluorescence will be retained in hepatocyte. For cell retain with NAC and without NAC are almost the same. With NAC, the number of cell rupture decreases about 75%
机译:乙酰氨基酚(APAP)是全球着名的药物,服用过量的乙酰氨基酚会摄入肝细胞损伤。对于在过去40年来我们对肝细胞损伤机制的理解中,病理生理学的许多方面仍然未知或争议.1在这项研究中,将小鼠注射过量以破坏肝细胞。 Apap Deplete谷胱甘肽和细胞ATP,N-乙酰半胱氨酸(NAc)起到保护肝细胞受伤的重要作用。 N-乙酰半胱氨酸提供线粒体以产生谷胱甘肽以释放肝细胞的药物作用。通过6-羧基荧光素二乙酸酯(6-CFDA)体内代谢,谷胱甘肽在时间耗尽以观察肝细胞的形态。没有NAC,细胞坏死增加到血浆膜损伤到释放6-CFDA,这破裂。在6-CFDA注射后,荧光将保留在肝细胞中。对于细胞保留NAC,没有NAC几乎相同。随着NAC,细胞破裂的数量降低约75%

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