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In vivo N-acetyl cysteine reduce hepatocyte death by induced acetaminophen

机译:体内N-乙酰半胱氨酸通过诱导对乙酰氨基酚减少肝细胞死亡

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Acetaminophen (APAP) is the famous drug in global, and taking overdose Acetaminophen will intake hepatic cell injure. Desptie substantial progress in our understanding of the mechanism of hepatocellular injury during the last 40 years, many aspects of the pathophysiology are still unknown or controversial.1 In this study, mice are injected APAP overdose to damage hepatocyte. APAP deplete glutathione and ATP of cell, N-Acetyl Cysteine (NAC) plays an important role to protect hepatocytes be injury. N-Acetyl Cysteine provides mitochondrial to produce glutathione to release drug effect hepatocyte. By 6-carboxyfluorescein diacetate (6-CFDA) metabolism in vivo, glutathione keep depleting to observe the hepatocyte morphology in time. Without NAC, cell necrosis increase to plasma membrane damage to release 6-CFDA, that's rupture. After 6-CFDA injection, fluorescence will be retained in hepatocyte. For cell retain with NAC and without NAC are almost the same. With NAC, the number of cell rupture decreases about 75%
机译:对乙酰氨基酚(APAP)是全球著名的药物,过量服用对乙酰氨基酚会导致肝细胞损伤。尽管在过去40年中我们对肝细胞损伤机理的理解取得了实质性进展,但病理生理学的许多方面仍未知或有争议。1在这项研究中,向小鼠注射过量APAP会损伤肝细胞。 APAP消耗细胞的谷胱甘肽和ATP,N-乙酰半胱氨酸(NAC)在保护肝细胞受到损伤方面起着重要作用。 N-乙酰半胱氨酸提供线粒体产生谷胱甘肽以释放药物作用的肝细胞。通过体内的6-羧基荧光素二乙酸酯(6-CFDA)代谢,谷胱甘肽不断耗竭以及时观察肝细胞的形态。没有NAC,细胞坏死会增加质膜的损伤,从而释放6-CFDA,即破裂。 6-CFDA注射后,荧光将保留在肝细胞中。对于带有NAC和不带有NAC的细胞保留几乎相同。使用NAC,细胞破裂数减少了约75%

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