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Is Barrier Layer Responsible for Cellular Structure Of Aluminum Oxide Film Anodized in Sulfuric Acid?

机译:是否负责硫酸阳极氧化氧化铝膜的蜂窝结构的阻挡层?

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Increasing AC voltage in DC+AC process can reduce DC voltage to ~7 VDC that creates a strong enough electric field, forming a barrier layer with three areas. The closest to aluminum area has composition Al{sub}(2+q)O{sub}3 with higher concentration of aluminum ions. Above it there is pure dielectric: Al{sub}2O{sub}3-area. Area Al{sub}2O{sub}(3+p) close to electrolyte has higher concentration of oxygen ions. A weak (for example, boric) acid does not dissolve barrier layer. A strong (for example, sulfuric) acid finds a spot and dissolves barrier layer until the lowest area Al{sub}(2+q)O{sub}3 surrounding the spot is reached and flooded with oxygen ions. These ions transform Al{sub}(2+q)O{sub}3 into Al{sub}2O{sub}3 that builds up wall around the spot, forming a pore. Each spot is complemented equidistantly with six spots, building hexagonal cells with a pore in the center of each cell.
机译:DC + AC工艺中的AC电压增加可以将DC电压降低到〜7 VDC,从而产生足够强大的电场,形成有三个区域的阻挡层。最接近铝区域的组成Al {Sub}(2 + Q)O {亚} 3,浓度较高的铝离子。在它之上,存在纯电介质:Al {Sub} 2O {Sub} 3区域。接近电解质的区域Al {sub} 2O {sub}(3 + p)具有较高浓度的氧离子。弱(例如,硼酸)酸不溶解阻挡层。强(例如,硫酸)酸发现斑点并溶解阻挡层,直到达到斑点的最低区域Al {Sub}(2 + Q)O {Sub} 3,并用氧离子淹没。这些离子将Al {sub}(2 + q)o {sub} 3转换为al {sub} 2o {sub} 3,在斑点围绕斑点构成墙壁,形成孔隙。每个斑点与六个斑点相互作用,六个斑点,在每个细胞的中心建造六角形细胞。

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