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Strongly Universal Reversible Gate Sets

机译:强烈普遍的可逆门套

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It is well-known that the Toffoli gate and the negation gate together yield a universal gate set, in the sense that every permutation of {0, 1}~n can be implemented as a composition of these gates. Since every bit operation that does not use all of the bits performs an even permutation, we need to use at least one auxiliary bit to perform every permutation, and it is known that one bit is indeed enough. Without auxiliary bits, all even permutations can be implemented. We generalize these results to non-binary logic: For any finite set A, a finite gate set can generate all even permutations of A~n for all n, without any auxiliary symbols. This directly implies the previously published result that a finite gate set can generate all permutations of A~n when the cardinality of A is odd, and that one auxiliary symbol is necessary and sufficient to obtain all permutations when the cardinality of A is even. We also consider the conservative case, that is, those permutations of A~n that preserve the weight of the input word. The weight is the vector that records how many times each symbol occurs in the word. It turns out that no finite conservative gate set can, for all n, implement all conservative even permutations of A~n without auxiliary bits. But we provide a finite gate set that can implement all those conservative permutations that are even within each weight class of A~n.
机译:众所周知,Toffoli栅极和否定栅极一起产生通用栅极组,意义上是{0,1}〜N的每个置换可以作为这些门的组成来实现。由于不使用所有位的每个位操作执行均匀的排列,我们需要使用至少一个辅助位来执行每个置换,并且已知一位确实足够了。没有辅助比特,可以实现所有偶数排列。我们将这些结果概括为非二进制逻辑:对于任何有限的组A,有限栅极集可以为所有N产生均匀的A〜n的置换,而没有任何辅助符号。这直接暗示先前公布的结果,当A奇数是奇数时,有限栅极集可以产生〜n的所有排列,并且当甚至时,一个辅助符号是必要的并且足以获得所有置换。我们还考虑保守的案例,即〜n的那些保留输入词的重量的排列。重量是记录在单词中发生每个符号发生的次数的矢量。事实证明,没有有限保守的门设定可以为所有n实现所有保守派均匀的A〜N的置换而没有辅助比特。但是,我们提供了一个有限的栅极集合,可以实现甚至在每个重量等级内的所有那些保守置换。

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