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Orthogonal Graph Drawing with Inflexible Edges

机译:与不灵活的边缘的正交图

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We consider the problem of creating plane orthogonal drawings of 4-planar graphs (planar graphs with maximum degree 4) with constraints on the number of bends per edge. More precisely, we have a flexibility function assigning to each edge e a natural number flex(e), its flexibility. The problem FLEXDRAW asks whether there exists an orthogonal drawing such that each edge e has at most flex(e) bends. It is known that FLEXDRAW is NP-hard if flex(e) = 0 for every edge e [7]. On the other hand, FLEXDRAW can be solved efficiently if flex(e) ≥ 1 [2] and is trivial if flex(e) ≥ 2 [1] for every edge e. To close the gap between the NP-hardness for flex(e) = 0 and the efficient algorithm for flex(e) ≥ 1, we investigate the computational complexity of FLEXDRAW in case only few edges are inflexible (i.e., have flexibility 0). We show that for any ε > 0 FLEXDRAW is NP-complete for instances with O(n~ε) inflexible edges with pairwise distance Ω(n~(1-ε)) (including the case where they induce a matching). On the other hand, we give an FPT-algorithm with running time O(2~k·n·T_(flow)(n)), where T_(flow)(n) is the time necessary to compute a maximum flow in a planar flow network with multiple sources and sinks, and k is the number of inflexible edges having at least one endpoint of degree 4.
机译:我们考虑创建4平面图的平面正交图(具有最大程度的平面图),每个边缘的弯曲数量的约束。更确切地说,我们具有为每个边缘E分配的灵活性功能,自然数Flex(E),其灵活性。问题FlexDraw询问是否存在正交绘制,使得每个边缘E具有大多数柔性(e)弯曲。众所周知,如果每个边缘E的Flex(e)= 0,FlexDraw是NP-HARD [7]。另一方面,如果弯曲(e)≥1[2],可以有效地解决FlexDraw,并且如果每个边缘e≥2[1],则弯曲(e)≥2[1]是微不足道的。为了缩小弯曲(E)= 0的NP硬度之间的间隙和柔性(e)≥1的有效算法,我们调查FlexDraw的计算复杂性,因为只有很少的边缘是不灵活的(即,具有灵活性0)。我们表明,对于任何ε> 0,FlexDraw是NP-Complete,用于具有O(n〜ε)的情况,具有成对距离ω(n〜(1-ε))(包括它们诱导匹配的情况)。另一方面,我们给出了运行时间O的FPT算法O(2〜k·n·t_(flow)(n)),其中t_(flow)(n)是计算a中最大流量所需的时间具有多个源和沉积的平面流量网络,k是具有至少一个4个终点的凹形边的数量。

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