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Orthogonal Graph Drawing with Inflexible Edges

机译:具有不固定边缘的正交图

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We consider the problem of creating plane orthogonal drawings of 4-planar graphs (planar graphs with maximum degree 4) with constraints on the number of bends per edge. More precisely, we have a flexibility function assigning to each edge e a natural number flex(e), its flexibility. The problem FlexDraw asks whether there exists an orthogonal drawing such that each edge e has at most flex(e) bends. It is known that FlexDraw is NP-hard if flex(e) = 0 for every edge e. On the other hand, FlexDraw can be solved efficiently if flex(e) ≥ 1 and is trivial if flex(e) ≥ 2 for every edge e. To close the gap between the NP-hardness for flex(e) = 0 and the efficient algorithm for flex(e) ≥ 1, we investigate the computational complexity of FlexDraw in case only few edges are inflexible (i.e., have flexibility 0). We show that for any e ≥ 0 FlexDraw is NP-complete for instances with O(n~ε) inflexible edges with pairwise distance Ω(n~(1-ε)) (including the case where they induce a matching). On the other hand, we give an FPT-algorithm with running time O(2~k • n • T_(flow)(n)), where T_flow)(n) is the time necessary to compute a maximum flow in a planar flow network with multiple sources and sinks, and k is the number of inflexible edges having at least one endpoint of degree 4.
机译:我们考虑创建具有限制每个边的弯曲数的4平面图(最大度数为4的平面图)的平面正交图的问题。更准确地说,我们具有一个灵活性函数,为每个边缘e分配一个自然数flex(e),即其灵活性。问题FlexDraw询问是否存在正交图,以便每个边缘e最多具有flex(e)弯曲。众所周知,如果每个边缘e的flex(e)= 0,FlexDraw都是NP-hard。另一方面,如果flex(e)≥1,则FlexDraw可以有效求解;如果每个边缘e的flex(e)≥2,则FlexDraw都是微不足道的。为了缩小flex(e)= 0的NP硬度与flex(e)≥1的高效算法之间的差距,我们研究了在只有很少的边缘是不灵活的(即,灵活性为0)的情况下FlexDraw的计算复杂性。我们表明,对于任何e≥0的情况,对于具有成对距离Ω(n〜(1-ε))的O(n〜ε)个不可弯曲边缘的实例,FlexDraw是NP完全的(包括它们引起匹配的情况)。另一方面,我们给出运行时间为O(2〜k•n•T_(flow)(n))的FPT算法,其中T_flow)(n)是计算平面流中最大流所需的时间具有多个源和汇的网络,k是具有至少一个4度端点的不挠边的数量。

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