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Why certain liquids have the liquid crystal properties?

机译:为什么某些液体具有液晶特性?

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The creation reasons of liquid crystal state have not explained up to now. This article is devoted for the elaboration a new solution of this problem. Author found the new calculation method of expression Σ(r_i)~2 which is a function of temperature, molecular weight and light wavelength. The Σ(r_i)~2 characterise the molecule of liquid and is connected with the distance polarizability tensor components α_(||1), α_(⊥1) by the formula. Σ(r_i)~2 = ( Z r_o)~(1/2) [(α_(||1))~(1/2)/2 + (α_(⊥1))~(1/2)]. For liquid crystal one can obtain two values of Σ(r_i)~2. First the Σ(r_i)~2_(T_o) for the transition temperature T_o the isotropic liquid state of liquid crystal and second Σ(r_i)~2_(T_c) for the transition temperature to the solid state of liquid Crystal. These quantities must to satisfy the relation Σ(r_i)~2_(T_o) < Σ(r_i)~2_(T_c) for all liquid crystals. If it is inversely the liquid does not posses the liquid crystal properties.
机译:液晶状态的创造原因尚未解释到现在。本文致力于阐述这一问题的新解决方案。作者发现了表达式σ(R_I)〜2的新计算方法,其是温度,分子量和光波长的函数。 σ(r_i)〜2表征液体分子,并通过公式与距离极化性张量组分α_(|| 1),α_(⊥1)连接。 σ(r_i)〜2 =(z r_o)〜(1/2)[(α_(|| 1))〜(1/2)/ 2 +(α_(⊥1))〜(1/2)]。对于液晶,可以获得两个值σ(R_I)〜2的值。首先是转变温度T_O的σ(R_I)〜2_(T_O)T_O的各向同性液体状态和用于转变温度的液晶和第二σ(R_I)〜2_(T_C)的各向同性液体状态。这些数量必须满足所有液晶的关系σ(r_i)〜2_(t_o)〜2_(t_i)。如果其成反比,则液体不具有液晶特性。

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