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Design of Fault Tolerant Satellite Networks with Priorities via Selectors

机译:通过选择器设计具有优先级的容错卫星网络的设计

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We consider on-board networks in satellites interconnecting entering signals (inputs) to amplifiers (outputs). The connections are made via expensive switches with four links available. The paths connecting inputs to outputs should be link-disjoint. Among the input signals, some of them, called priorities, must be connected to the amplifiers which provide the best quality of service (that is to some specific outputs). In practice, amplifiers are subject to faults that cannot be repaired. Therefore we need to add extra outputs to ensure the existence of sufficiently many valid ones. Given n inputs, p priorities and k faults, the problem consists in designing a low cost network (i. e. with the minimum number of switches) where it is possible to route the p priorities to the p best quality amplifiers and the other inputs to some valid amplifiers, for any sets of k faulty and p best quality amplifiers. Let N(n,p,k) be the minimum number of switches of a such a network, called repartitor. In [3], it was proved that N(n, p, 0) ≤ n - p + (n/2) [log_2 p] and some exact values of N(n,p,k) were given when p and k are small. A (n, 0, k)-repartitor (or a (n, n, k)-repartitor) is called a (n, n+k)-selector and the minimum number of switches of a (p,n)-selector is denoted by S(p,n). A selector is intrinsically easier to design than general repartitors since there exists only one type of signals to route instead of two. The approach of this paper is to construct (n,p,k)-repartitors from selectors. We show that and N(n,p,k) ≤ S(p,p + k) + S(n + k,p + k) +S(n -p,p + k). Then we prove that S(p,n) ≤ 33n+4p+O(logn) which implies N(n,p,k) ≤ 71n + 37p + 108k+ O(log(n + k)). At last, we study (p,n)-selectors when p is fixed. We prove that: if p is even then S(p,n) ≥(2~(p/2)―1)/(2~(p/2)) n+θ(1); if p us odd then S(p,n) ≥(2~((p+3)/2)―3)/(2~((p+3)/2)) n+θ(1). We conjecture that equality holds and show it for p ≤ 6.
机译:我们考虑在卫星中的板载网络互连输入信号(输入)到放大器(输出)。连接通过具有可用四个链路的昂贵开关进行。将输入连接到输出的路径应该是链路脱节。在输入信号中,其中一些称为优先级必须连接到放大器,该放大器提供最佳服务质量(即某些特定输出)。在实践中,放大器受到无法修复的故障的影响。因此,我们需要添加额外的输出,以确保存在足够许多有效的输出。给定N个输入,P优先级和K故障,问题在于设计低成本网络(即具有最小交换机的最小数量),可以将P优先级路由到P优质放大器和其他输入有效放大器,适用于任何套的k故障和P优质放大器。设n(n,p,k)是这样的网络的最小交换机,称为repartitor。在[3]中,证明N(n,p,0)≤n-p +(n / 2)[log_2 p]和n(n,p,k)的某些确切值在p和k时给出很小。 a(n,0,k)-repartitor(或(n,n,k)-repartitor)称为(n,n + k) - 选择器和a(p,n)选择的最小交换机数由s(p,n)表示。选择器比常规递送者在本质上更容易地设计,因为只有一种类型的信号而不是两个的信号。本文的方法是从选择器构建(n,p,k)-repartorors。我们展示了N(n,p,k)≤s(p,p + k)+ s(n + k,p + k)+ s(n -p,p + k)。然后,我们证明了S(p,n)≤33n+ 4p + o(logn)意味着n(n,p,k)≤71n+ 37p + 108k + o(log(n + k))。最后,我们在P是固定时学习(P,N)选择器。我们证明:如果P是s(p,n)≥(2〜(p / 2)-1)/(2〜(p / 2))n +θ(1);如果P USY off那么s(p,n)≥(2〜((p + 3)/ 2)-3)/(2〜((p + 3)/ 2))n +θ(1)。我们猜想平等持有并显示P≤6。

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