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Noisy Guesses

机译:嘈杂的猜测

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摘要

We consider the problem of guessing a random, finite–alphabet, secret n–vector, where the guesses are transmitted via a noisy channel. We provide a single–letter formula for the best achievable exponential growth rate of the ρ–th moment of the number of guesses, as a function of n. This formula exhibits a fairly clear insight concerning the penalty due to the noise. We describe two different randomized schemes that achieve the optimal guessing exponent. One of them is fully universal in the sense of being independent of source (that governs the vector to be guessed), the channel (that corrupts the guesses), and the moment power ρ. Interestingly, it turns out that, in general, the optimal guessing exponent function exhibits a phase transition when it is examined either as a function of the channel parameters, or as a function of ρ: as long as the channel is not too distant (in a certain sense to be defined precisely) from the identity channel (i.e., the clean channel), or equivalently, as long ρ is larger than a certain critical value, ρc, there is no penalty at all in the guessing exponent, compared to the case of noiseless guessing.
机译:我们考虑猜测一个随机的,有限字母的秘密n矢量的问题,其中猜测是通过一个嘈杂的信道传输的。我们为猜测次数的第ρ时刻的最佳可实现指数增长率提供了一个单字母公式,它是n的函数。该公式对噪声造成的损失显示出相当清晰的见解。我们描述了实现最佳猜测指数的两种不同的随机方案。其中之一是完全通用的,它与源(控制要猜测的向量),通道(破坏猜测)和力矩功率ρ无关。有趣的是,事实证明,通常,当根据信道参数或作为ρ的函数对最佳猜测指数函数进行检查时,只要信道距离不太远(在从标识通道(即干净通道)精确定义的某种意义,或者等效地,只要ρ大于某个临界值ρ c 与无噪声猜测的情况相比,猜测指数完全没有损失。

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