【24h】

0/1 Polytopes with Quadratic Chvatal Rank

机译:0/1具有二次Chvatal等级的多粒子

获取原文

摘要

For a polytope P, the Chvatal closure P' (is contained in) P is obtained by simultaneously strengthening all feasible inequalities cx ≤ β (with integral c) to cx ≤ [β]. The number of iterations of this procedure that are needed until the integral hull of P is reached is called the Chvatal rank. If P (is contained in) [0, 1]~n, then it is known that O(n~2 log n) iterations always suffice (Eisenbrand and Schulz (1999)) and at least (1 + 1/e - o(1))n iterations are sometimes needed (Pokutta and Stauffer (2011)), leaving a huge gap between lower and upper bounds. We prove that there is a polytope contained in the 0/1 cube that has Chvatal rank Ω(n~2), closing the gap up to a logarithmic factor. In fact, even a superlinear lower bound was mentioned as an open problem by several authors. Our choice of P is the convex hull of a semi-random Knapsack polytope and a single fractional vertex. The main technical ingredient is linking the Chvatal rank to simultaneous Diophantine approximations w.r.t. the ‖ · ‖_1-norm of the normal vector defining P.
机译:对于多晶硅p,通过同时强化所有可行的不等式Cx≤β(用整体C)至Cx≤[β],获得Chvatal闭合P'(包含在)p。在达到P的整体船体之前所需的该过程的迭代次数称为Chvatal等级。如果p(包含在)[0,1]〜n,则已知O(n〜2 log n)迭代始终足够(Eisenbrand和Schulz(1999)),并且至少(1 + 1 / E - O. (1))有时需要迭代(Pokutta和Stauffer(2011)),留下下限和上限之间的巨大差距。我们证明有一个包含在0/1立方体中的多容素,具有Chvatal等级ω(n〜2),将差距关闭到对数因子。事实上,即使是几位作者被提到的超线性下限也被提到是一个公开问题。我们选择的P是半随机背包多容孔的凸壳和单个分数顶点。主要的技术成分是将Chvatal等级连接到同时蒸氨酸近似值w.r.t. ‖·‖_1-norm的正常矢量定义p。

著录项

相似文献

  • 外文文献
  • 中文文献
  • 专利
获取原文

客服邮箱:kefu@zhangqiaokeyan.com

京公网安备:11010802029741号 ICP备案号:京ICP备15016152号-6 六维联合信息科技 (北京) 有限公司©版权所有
  • 客服微信

  • 服务号