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The Approximability of the p-hub Center Problem with Parameterized Triangle Inequality

机译:参数三角不等式的p-hub中心问题的逼近度

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A complete weighted graph G = (V,E,w) is called ∆_β-metric, for some β ≥ 1/2, if G satisfies the β-triangle inequality, i.e., w(u,v) ≤ β · (w(u,x) + w(x,v)) for all vertices u,v,x ∈ V. Given a ∆_β-metric graph G = (V,E,w) and an integer p, the ∆_β-pH+_(UB) Center Problem (∆_β-pHCP) is to find a spanning subgraph H~* of G such that (i) vertices (hubs) in C~*⊂V form a clique of size p in H~*; (ii) vertices (non-hubs) in VC~* form an independent set in H~*; (iii) each non-hub v ∈ VC~* is adjacent to exactly one hub in C~*; and (iv) the diameter D(H~*) is minimized. For β = 1, ∆_β-pHCP is NP-hard. (Chen et al., CMCT 2016) proved that for any ε > 0, it is NP-hard to approximate the ∆_β-pHCP to within a ratio 4/3 - ε for β = 1. In the same paper, a 5/3-approximation algorithm was given for ∆_β-pHCP for β = 1. In this paper, we study ∆_β-pHCP for all β ≥1/2. We show that for any ε > 0, to approximate the ∆_β-pRCP to a ratio g(β) - ε is NP-hard and we give r(β)-approximation algorithms for the same problem where g(β) and r(β) are functions of β. If β ≤ (3-√3)/2, we have r(β) = g(β) = 1, i.e., ∆_β-pHCP is polynomial time solvable. If (3-√3)/2 < β ≤ 2/3, we have r(β) = g(β) = (3β-2β~2)/(3(1-β)). For 2/3 ≤ β ≤ (5+√5)/(10), r(β) = g(β) = β + β~2. Moreover, for β ≥ 1, we have g(β) = β ·(4β-1)/(3β-1) and r(β) = 2β, the approximability of the problem (i.e., upper and lower bound) is linear in β.
机译:如果G满足β三角不等式,即w(u,v)≤β·(w (u,x)+ w(x,v))对于所有顶点u,v,x∈V.给定∆_β-度量图G =(V,E,w)和整数p,则∆_β-pH + _(UB)中心问题(∆_β-pHCP)是找到G的一个跨越子图H〜*,使得(i)C〜*⊂V中的顶点(集线器)形成H〜*中大小为p的团; (ii)V \ C〜*中的顶点(非集线器)在H〜*中形成独立的集合; (iii)每个非集线器v∈V \ C〜*都恰好与C〜*中的一个集线器相邻; (iv)使直径D(H〜*)最小。对于β= 1,∆_β-pHCP是NP-hard。 (Chen et al。,CMCT 2016)证明,对于任何ε> 0,对于β= 1,将Δ_β-pHCP近似在4/3-ε的比率内都是NP难的。在同一篇论文中,5对于β= 1的Δ_β-pHCP,给出了/ 3-近似算法。在本文中,我们针对所有β≥1/ 2的Δ_β-pHCP进行研究。我们证明对于任何ε> 0,将Δ_β-pRCP近似为g(β)-ε是NP-hard的,对于相同的问题,我们给出r(β)近似算法,其中g(β)和r (β)是β的函数。如果β≤(3-√3)/ 2,则r(β)= g(β)= 1,即∆_β-pHCP是多项式时间可解的。如果(3-√3)/ 2 <β≤2/3,则r(β)= g(β)=(3β-2β〜2)/(3(1-β))。对于2/3≤β≤(5 +√5)/(10),r(β)= g(β)=β+β〜2。此外,对于β≥1,我们有g(β)=β·(4β-1)/(3β-1)和r(β)=2β,问题的逼近度(即上下界)是线性的在β中。

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