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The Visible Perimeter of an Arrangement of Disks

机译:磁盘排列的可见范围

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Given a collection of n opaque unit disks in the plane, we want to find a stacking order for them that maximizes their visible perimeter, the total length of all pieces of their boundaries visible from above. We prove that if the centers of the disks form a dense point set, i.e., the ratio of their maximum to their minimum distance is O(n~(1/2)), then there is a stacking order for which the visible perimeter is Ω(n~(2/3)). We also show that this bound cannot be improved in the case of the n~(1/2) × n~(1/2) piece of a sufficiently small square grid. On the other hand, if the set of centers is dense and the maximum distance between them is small, then the visible perimeter is O(n~(3/4)) with respect to any stacking order. This latter bound cannot be improved either. These results partially answer some questions of Cabello, Haverkort, van Kreveld, and Speckmann.
机译:给定平面中n个不透明单位圆盘的集合,我们希望找到它们的堆叠顺序,以最大化其可见周长,即从上方可见的所有边界边界的总长度。我们证明,如果圆盘的中心形成一个密集点集,即最大圆盘与最小圆盘的距离之比为O(n〜(1/2)),则存在可见周长为Ω(n〜(2/3))。我们还表明,在n〜(1/2)×n〜(1/2)个足够小的正方形网格的情况下,无法改善此边界。另一方面,如果中心的集合密集并且它们之间的最大距离很小,则相对于任何堆叠顺序,可见周长为O(n〜(3/4))。后者的界限也不能改善。这些结果部分回答了Cabello,Haverkort,van Kreveld和Speckmann的一些问题。

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