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Flip Distance between Triangulations of a Simple Polygon is NP-Complete

机译:简单多边形的三角剖分之间的翻转距离是NP完全的

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Let T be a triangulation of a simple polygon. A flip in T is the operation of removing one diagonal of T and adding a different one such that the resulting graph is again a triangulation. The flip distance between two triangulations is the smallest number of flips required to transform one triangulation into the other. For the special case of convex polygons, the problem of determining the shortest flip distance between two triangulations is equivalent to determining the rotation distance between two binary trees, a central problem which is still open after over 25 years of intensive study. We show that computing the flip distance between two triangulations of a simple polygon is NP-complete. This complements a recent result that shows APX-hardness of determining the flip distance between two triangulations of a planar point set.
机译:令T为简单多边形的三角剖分。 T的翻转是删除T的一个对角线并添加另一个对角线,以使所得图形再次成为三角剖分的操作。两个三角剖分之间的翻转距离是将一个三角剖分转换为另一个三角剖分所需的最小翻转次数。对于凸多边形的特殊情况,确定两个三角剖分之间的最短翻转距离的问题等同于确定两个二叉树之间的旋转距离的问题,这个中心问题在经过25年的深入研究后仍然存在。我们表明,计算简单多边形的两个三角剖分之间的翻转距离是NP完全的。这补充了最近的结果,该结果显示了确定平面点集的两个三角剖分之间的翻转距离的APX难度。

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