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Earthwork

机译:土方制动

摘要

Problem to be solved: to provide an earthenware material in which the eluting amount of heavy metals is small despite the use of waste containing heavy metals.Solution: the waste material containing heavy metals and the granular material containing ferrous chloride, and the ratio of the ratio of Fe (Fe2O3) to Mg (Fe2O3) and the ratio of Mg (MgO conversion) in the mass of 100 mass% excluding the total weight of the earthwork material to the loss of strong heat, is 1.0 to The material of the ratio of CL to the ratio of S (SO3 conversion) is 0.45 to 2.30.A mixing step of mixing a mixture containing heavy metals and ferrous chloride to obtain a mixture andGranulated the mixtureIt is an earthenware material made of granular materialIn the mass 100% by mass from the total mass of the earthwork material except for the strong heat lossThe ratio of Fe (Fe2O3) to Mg (MgO conversion) is from 1.0 toA method of manufacturing an earthenware material comprising a granulation process for obtaining a clay material having a ratio of CL to a ratio of S (SO3) to 0.45 to 2.30.No selection
机译:要解决的问题:提供一种陶器材料,其中虽然使用含有重金属的废物,但重金属的洗脱量很小。溶液:含有重金属的废料和含有氯化亚铁的颗粒材料,Fe(Fe 2 O 3)与Mg(Fe 2 O 3)的比例和Mg(MgO转化)的比例免于100质量%之外土工材料的总重量与强热量的损失,是Cl到S(SO 3转化)的比例的比例为0.45-2.30.混合含有重金属和氯化亚铁的混合物的混合步骤为了获得混合物和解的混合物,搅拌物质是由粒状物质制成的陶器材料,除了Fe(Fe 2 O 3)的强热滞后比例除了碎石材料的总质量,除了Fe(Fe2O3)至Mg(MgO转化)的总质量为1.0制造陶器材料的方法,包括造粒方法,用于获得具有Cl与S(SO 3)的比率与0.45至2.30的比率的粘土材料.NO选择

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