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SPACE PRODUCT SUM ARITHMETIC UNIT

机译:空间积和算术单元

摘要

PURPOSE:To perform space product sum arithmetic at a high speed by using two 1st shift registers for storage of the interim result of arithmetic and apply ing the outputs of both shift registers to the 2nd adder in the form of high-order 8 bits and low-order 8 bits respectively. CONSTITUTION:The F2 and F2, F1 and F2 and F0 and F2 are supplied with shifts to registers 38, 39 and 40 by shift clocks SCLK1-3 respectively. Then the sum of the 1st and 2nd arithmetic results of F1 and F1 is delivered from shift registers 24 and 25 respectively. The output of an adder 48 is equal to the space product sum arithmetic result of the F1 and F1 respectively. The above-mentioned arithmetic is repeated to set F255 and F2, F254 and F2 and F253 and F2 to registers 38-40 respectively. When the 3rd arithmetic is through with F254 and F1, the optional continuous 8 bits of the space product sum arithmetic results of F0,1-F255,1 are stored in a shift register 23. At the same time, the high-order 8 bits and low-order 8 bits are stored in the registers 24 and 25 respectively. This shortens the reading time and therefore increases the overall processing speed.
机译:目的:通过使用两个第一移位寄存器来存储算术的中间结果,并以高阶8位和低位形式将两个移位寄存器的输出应用于第二加法器,以高速执行空间积和算术分别为8位。组成:F2和F2,F1和F2以及F0和F2分别通过移位时钟SCLK1-3提供移位到寄存器38、39和40。然后,分别从移位寄存器24和25传送F1和F1的第一和第二算术结果的和。加法器48的输出分别等于F1和F1的空间积和运算结果。重复上述运算,以分别将F255和F2,F254和F2以及F253和F2设置到寄存器38-40。当F254和F1进行第三次运算时,F0,1-F255,1的空间积和运算结果的可选连续8位存储在移位寄存器23中。与此同时,高阶8位低位8位和低位8位分别存储在寄存器24和25中。这缩短了读取时间,因此提高了整体处理速度。

著录项

  • 公开/公告号JPS61241879A

    专利类型

  • 公开/公告日1986-10-28

    原文格式PDF

  • 申请/专利权人 FANUC LTD;

    申请/专利号JP19850083337

  • 发明设计人 KURAKAKE MITSUO;OTSUKA SHOICHI;

    申请日1985-04-18

  • 分类号G06F17/10;G06F17/16;G06T5/20;

  • 国家 JP

  • 入库时间 2022-08-22 07:48:35

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