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SPACE PRODUCT SUM ARITHMETIC UNIT

机译:空间积和算术单元

摘要

PURPOSE:To perform space product sum arithmetic at a high speed by using a control circuit to obtain data delivered from the 2nd adder as the result of each space product sum arithmetic of the picture element data equivalent to a line and to be processed while the last line of a coefficient memory is controlled. CONSTITUTION:When an X counter is set at O when the processing is over, both F0 and F1 are set to a register 33. At the same time, the registers W3,1-W1,1 are set to registers 36-38 together with F1 and F1 set to a register 33 respectively. Then F0 and F1 are set to a register 34 with a shift clock SCLK1 for execution of the 1st arithmetic of the F0 and F2. The result of this arithmetic is obtained by an adder 47. Hereafter, the space product sum arithmetic is carried out for the picture element data on the 2nd and its follow ing lines respectively. A controller 19 switches multiplexers 29 and 39 to the side of a system address bus 52 with a stop command. Thus a main CPU 26 can have access to the 2nd frame memory 21 and reads the result of arithmetic out of the memory 21 via a data transmitter/receiver 25 to recognize it. In such a way, the picture data can be processed at a high speed.
机译:目的:通过使用控制电路来高速执行空间积和算术,以获取从第二加法器传送的数据,作为等效于一行的像素数据的每个空间积和算法的结果,最后处理一次系数存储器的线被控制。组成:当处理结束时,将X计数器设置为O时,F0和F1都被设置到寄存器33。同时,寄存器W3,1-W1,1与其他寄存器一起被设置到寄存器36-38。 F1和F1分别设置到寄存器33。然后,将F0和F1设置到具有移位时钟SCLK1的寄存器34,以执行F0和F2的第一运算。该算术的结果由加法器47获得。此后,分别对第二行及其后续行的像素数据执行空间积和算法。控制器19利用停止命令将多路复用器29和39切换到系统地址总线52的一侧。因此,主CPU 26可以访问第二帧存储器21,并且经由数据发送器/接收器25从存储器21中读取算术结果以对其进行识别。这样,可以高速处理图像数据。

著录项

  • 公开/公告号JPS61241877A

    专利类型

  • 公开/公告日1986-10-28

    原文格式PDF

  • 申请/专利权人 FANUC LTD;

    申请/专利号JP19850083334

  • 发明设计人 KURAKAKE MITSUO;OTSUKA SHOICHI;

    申请日1985-04-18

  • 分类号G06F17/10;G06F17/15;G06F17/16;G06T1/00;G06T1/20;G06T5/20;

  • 国家 JP

  • 入库时间 2022-08-22 07:48:35

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