首页> 外国专利> How to convert enantiomers - (2R, 3R) (2S, 3S) -2-amino-3-phenyl-1,3-propanediol

How to convert enantiomers - (2R, 3R) (2S, 3S) -2-amino-3-phenyl-1,3-propanediol

机译:如何转换对映异构体-(2R,3R)(2S,3S)-2-氨基-3-苯基-1,3-丙二醇

摘要

PURPOSE: To obtain (2R,3R)enantiomers effectively used in the synthesis of a compound having an antibiotic action, by successively carrying out the epimerization of only 2-position carbon atom combined with an amino group of a titled compound, and the epimerization of only 3-position benzyl carbon. ;CONSTITUTION: The OH group and NH2 group at the 3-position of (2S,3S) enantiomer of a compound of formula (X is H, NO2, CH3S, CH3SO, CH3SO2) are protected, then the hydroxymethyl group is oxidized to formyl or formyl derivative, carboxyl or carboxyl derivative by Swan-Moffatt oxidation, etc., and then a C atom at the α-position relative to the oxidized group is epimerized under an acid or base condition. The oxidized group of the obtained compound is reduced with a neutral reducing agent to be restored to the primary alcohol, the protective group introduced in the first process, is removed, and the benzyl carbon of 3-position is epimerized with acetic anhydride and p-toluenesulfonic anhydride, to obtain (2R,3R)enantiomer.;COPYRIGHT: (C)1991,JPO
机译:用途:通过依次进行仅2位碳原子与标题化合物的氨基结合的差向异构化反应以及与下列化合物的差向异构化反应,来获得有效用于合成具有抗生素作用的化合物的(2R,3R)对映异构体仅3-位苄基碳。 ;组成:式(X为H,NO 2 ,CH的化合物)的(2S,3S)对映异构体3位的OH和NH 2 基团保护 3 S,CH 3 SO,CH 3 SO 2 ),然后将羟甲基氧化为甲酰基或甲酰基衍生物,通过Swan-Moffatt氧化产生的羧基或羧基衍生物等,然后在酸或碱条件下将相对于氧化基团的α-位的C原子异构化。用中性还原剂将所得化合物的氧化基还原,还原成伯醇,除去第一步中引入的保护基,然后用乙酸酐和对-甲基苯酚将3-位苄基碳异构化。甲苯磺酸酐,制得(2R,3R)对映体。; COPYRIGHT:(C)1991,JPO

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