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The cast piece and its production manner null for the black sheet whose inclusion physical properties defect

机译:夹杂物的物理性质缺陷的黑片的铸件及其生产方式无效

摘要

PROBLEM TO BE SOLVED: To obtain a cast piece which does not depend on the contents of Mn, Si and Al and small in defects caused by inclusions by controlling the number of oxide inclusions with specified size and the number of alumina cluster inclusions in a of carbon steel contg. specified rations of C, Mn, Si, P, S, Al, Ti, Ca, N, oxygen, and the balance iron with inevitable impurities to not more than the specified value. ;SOLUTION: This carbon steel has a compsn. contg., by weight, 0.001 to 0.2% C, 0.01 to 0.5% Mn, 0.001 to 0.5% Si, 0.001 to 0.3% P, 0.0005 to 0.05% S, 0.006 to 0.1% Al, 0.005 to 0.06% Ti, 0.0005 to 0.01% Ca, 0.0005 to 0.01% N, 0.0005 to 0.0050% oxygen, and the balance iron with inevitable impurities. In the slab, the number of oxide inclusions of ≥53 μm is ≥200 pieces/kg, and the number of alumina cluster inclusions is ≤20 pieces/kg. C deoxidation is executed in an evacuated atmosphere, furthermore, Ti and Ca are successively added thereto, oxygen in the molten steel is removed, and, thereafter, Al is added to suppress the growth of the crystal grains of the steel.;COPYRIGHT: (C)2000,JPO
机译:解决的问题:通过控制一定尺寸的氧化物夹杂物的数量和氧化铝簇中的氧化铝簇状夹杂物的数量,获得一种不依赖于Mn,Si和Al的含量以及由夹杂物引起的缺陷少的铸件。碳素钢续C,Mn,Si,P,S,Al,Ti,Ca,N,氧和带有不可避免的杂质的余量铁的规定比例不得超过规定值。 ;解决方案:此碳素钢具有成分。以重量计,包括0.001至0.2%C,0.01至0.5%Mn,0.001至0.5%Si,0.001至0.3%P,0.0005至0.05%S,0.006至0.1%Al,0.005至0.06%Ti,0.0005至0.5% 0.01%Ca,0.0005至0.01%N,0.0005至0.0050%氧气以及余量的铁中不可避免地存在杂质。在平板中,≥53μm的氧化物夹杂物的数量为≥200个/ kg,氧化铝簇状夹杂物的数量为≥20个/ kg。 C的氧化是在真空气氛中进行的,然后依次添加Ti和Ca,除去钢水中的氧气,然后添加Al以抑制钢晶粒的生长。 C)2000年

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