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Method for calculating characteristic curve of centrifugal fluid machine by computer
Method for calculating characteristic curve of centrifugal fluid machine by computer
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机译:计算机计算离心机特征曲线的方法
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摘要
A computer-implemented method of calculating various types of characteristic curves of a centrifugal fluid machine according to the present invention can easily calculate a Q-H characteristic curve, a Q-E characteristic curve, a Q-NPSH characteristic curve, or the like. The method of calculating various types of characteristic curves uses two prescribed characteristic curves Y1=a11+a12x+a13x2+ . . . +a1nx(n−1) and Y2=a21+a22x+a23x2+ . . . +a2nx(n−1) formed of high-order equations for a centrifugal fluid machine to calculate a characteristic curve Y3=b1+b2x+b3x2+ . . . +bnx(n−1) formed of a high-order equation which passes through different coordinates (x3, y3). The method of calculating various types of characteristic curves selects prescribed coordinates (x1, y1) on the characteristic curve Y1 and corresponding prescribed coordinates (x2, y2) on the characteristic curve Y2, and calculates and outputs a characteristic curve Y3=b1+b2x+b3x2+ . . . +bnx(n−1) formed of a high-order equation which passes through different coordinates (x3, y3), with use of an equation bn={a1nkh1(1/kq1)(n−1)×(y3−y2)/(y1−y2)}+{a2nkh2(1/kq2)(n−1)×(y1−y3)/(y1−y2)}.
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机译:根据本发明的计算机实现的计算离心流体机器的各种类型的特性曲线的方法可以容易地计算Q-H特性曲线,Q-E特性曲线,Q-NPSH特性曲线等。计算各种类型的特征曲线的方法使用两个规定的特征曲线Y 1 B>等于a 11 Sub>+ a 12 Sub> x+ a 13 Sub> x 2 Sup>+ 。 。 。 + a 1n Sub> x (n− 1) Sup>和Y 2 B>= a 21 Sub>+ a 22 Sub> x+ a 23 Sub> x 2 Sup>+ 。 。 。由离心流体机的高阶方程组成的+ a 2n Sub> x (n− 1) Sup>来计算特性曲线Y 3 B> ; b 1 Sub>+ b 2 Sub> x+ b 3 Sub> x 2 Sup>+ 。 。 。 + b n Sub> x (n− 1) Sup>由通过不同坐标(x 3 Sub>,y 3 Sub>)。计算各种类型的特征曲线的方法选择特征曲线Y 1 B>上的指定坐标(x 1 Sub>,y 1 Sub>)和相应的指定坐标特征曲线Y 2 b>上的(x 2 Sub>,y 2 Sub>)并计算并输出特征曲线Y 3 B >= b 1 Sub>+ b 2 Sub> x+ b 3 Sub> x 2 Sup>+ 。 。 。 + b n Sub> x (n− 1) Sup>由通过不同坐标(x 3 Sub>,y 3 Sub>),并使用公式b n Sub>={ a 1n Sub> kh 1 Sub>(1 / kq 1 Sub>)(n− 1) Sup>×(y 3 Sub>− y 2 Sub>)/(y 1 Sub>− y 2 Sub>)}+{ a 2n Sub> kh 2 Sub>(1 / kq 2 Sub>)(n− 1) Sup>×(y 1 Sub>− y 3 Sub>)/(y 1 Sub> − y 2 Sub>)}。
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