首页>
外国专利>
APPARATUS, METHOD, AND PROGRAM FOR EVALUATING TOLERANCE LIMIT WITH RESPECT TO COEFFICIENT OF SIMULTANEOUS ALGEBRAIC EQUATION
APPARATUS, METHOD, AND PROGRAM FOR EVALUATING TOLERANCE LIMIT WITH RESPECT TO COEFFICIENT OF SIMULTANEOUS ALGEBRAIC EQUATION
展开▼
机译:关于同时代数方程的系数来评估公差极限的装置,方法和程序
展开▼
页面导航
摘要
著录项
相似文献
摘要
PROBLEM TO BE SOLVED: To provide a technology of evaluating a limit of permissible error ensuring that simultaneous equation ~f(x, y)=~g(x, y)=0 is solvable, from the bottom.;SOLUTION: A bivariate polynomial f(x, y), g(x, y)E*K[x, y] over a field K is written as follows (E* is a set symbol and represents "belong"): f(x, y)=ad(y)xd+ ... +a1(y)x+a0(y), g(x, y)=be(y)xe+ ... +b1(y)x+b0(y), wherein ad(y) and be(y) are not a constant 0. If both a requirement 1 [ad(y) and be(y) have no common zero] and a requirement 2 [Resx(f, g) is not a constant] are satisfied, f(x, y)=g(x, y)=0 has a solution (over a field of complex numbers). Resx(f, g) is a resultant of f(x, y) and g(x, y) for x. The proved fact is applied to the bivariate polynomial ~f(x, y), ~g(x, y) including an error in a coefficient.;COPYRIGHT: (C)2011,JPO&INPIT
展开▼
机译:解决的问题:提供一种评估允许误差极限的技术,以确保从底部开始求解联立方程〜f(x,y)=〜g(x,y)= 0;解决方案:二元多项式字段K上的f(x,y),g(x,y)E * K [x,y]的写法如下(E *为设定符号,表示“属于”):f(x,y)= a d Sub>(y)x d Sup> + ... + a 1 Sub>(y)x + a 0 Sub>( y),g(x,y)= b e Sub>(y)x e Sup> + ... + b 1 Sub>(y)x + b 0 Sub>(y),其中a d Sub>(y)和b e Sub>(y)不是常数0。如果两个条件都为1 [a d Sub>(y)和b e Sub>(y)没有共同的零]和要求2 [Res x Sub>(f,g) [不是一个常数]满足,则f(x,y)= g(x,y)= 0有一个解(在复数字段上)。 Res x Sub>(f,g)是x的f(x,y)和g(x,y)的结果。证明的事实适用于包含系数误差的二元多项式〜f(x,y),〜g(x,y).;版权:(C)2011,JPO&INPIT
展开▼