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Method of manufacturing a low yield ratio high-strength steel and low yield ratio high-strength steel

机译:低屈服比高强度钢和低屈服比高强度钢的制造方法

摘要

PROBLEM TO BE SOLVED: To provide a low yield-ratio high tensile-strength steel capable of obtaining high strength and a low yield ratio simultaneously with excellent weldability and low temperature toughness, and to provide a method for producing the low yield-ratio high tensile-strength steel.;SOLUTION: The low yield-ratio high tensile-strength steel contains steel components of, by mass, 0.01 to 0.08% C, ≤0.4% Si, 1.0 to 2.0% Mn, ≤0.02% P, ≤0.01% S, 0.005 to 0.06% Nb, 0.005 to 0.025% Ti, ≤0.06% Al and 0.001 to 0.005% N, in which PCM=C+Si/30+Mn/20+Cu/20+Ni/60+Cr/20+Mo/15+V/10+5B is 0.1 to 0.18%, and the balance iron with inevitable impurities. The total fraction of polygonal or quasi-polygonal ferrite and pearlite in the steel structure at a position of 1/4 thickness in the cross section in the sheet thickness direction is 50%, the Vickers hardness at a load of 98N in the bottom section of 1mm in the surface of the steel is ≤300 Hv, and the numerical value of a difference between the above Vickers hardness and the minimum value of the Vickers hardness measured at intervals of 1 mm to the cross-sectional direction in the sheet thickness of the steel is less than the numerical value 1.5 times the sheet thickness expressed by mm.;COPYRIGHT: (C)2007,JPO&INPIT
机译:解决的问题:提供一种能够同时获得高强度和低屈强比同时具有优异的可焊接性和低温韧性的低屈服比高拉伸强度钢,并提供一种生产低屈服比高拉伸强度的方法解决方案:低屈强比高拉伸强度钢包含质量分数为0.01到0.08%的C,0.4%的Si,1.0到2.0%的Mn,0.02%的P和le的钢成分。 ; 0.01%S,0.005至0.06%Nb,0.005至0.025%Ti,&le; 0.06%Al和0.001至0.005%N,其中P CM = C + Si / 30 + Mn / 20 + Cu / 20 + Ni / 60 + Cr / 20 + Mo / 15 + V / 10 + 5B为0.1〜0.18%,余量的铁具有不可避免的杂质。在薄板厚度方向上的横截面中厚度为1/4的位置的钢结构中,多边形或准多边形铁素体和珠光体的总含量<50%,底部的载荷为98N时的维氏硬度钢板表面的1mm的“ Vickers”为300Hv,上述维氏硬度与在板厚的截面方向上相距1mm的间隔处测得的维氏硬度的最小值之间的差的数值为钢的厚度小于以毫米为单位的板厚的1.5倍的数值。版权所有:(C)2007,日本特许厅

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