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The focus search device, the image analytical device, and in the device which among the focuses which

机译:焦点搜索设备,图像分析设备以及其中的哪个焦点

摘要

PPROBLEM TO BE SOLVED: To solve the problem that processing efficiency is poor in calculating each of distances from a plurality of adjacent points up to the most nearby feature point on a feature point map. PSOLUTION: A distance map, by which distances in the lateral direction from feature points are previously given to each point composing a two-dimensional arrangement, is generated (S30). In calculation stages, points forming one line and being positioned above and below points to be calculated are set as retrieval destinations, and distances to an obstacle is calculated by distances in the longitudinal direction from the points to be calculated up to the points of the retrieval destinations and values of the points of the retrieval destinations on the distance map (S34, S36). If the calculated values are smaller than the values at the previous retrieval destinations, the values are stored in a register (S38, S40). These procedures are repeated for all the retrieval destinations (S42). PCOPYRIGHT: (C)2008,JPO&INPIT
机译:

要解决的问题:为了解决在计算从多个相邻点到特征点地图上最接近的特征点的距离中的每一个时,处理效率差的问题。

解决方案:生成距离图,通过该距离图将到特征点的横向距离预先赋予组成二维排列的每个点(S30)。在计算阶段中,将形成一条线并位于要计算的点的上方和下方的点设置为检索目的地,并通过从要计算的点到检索点的纵向方向上的距离来计算到障碍物的距离。距离图上的检索目的地和检索目的地的点的值(S34,S36)。如果计算出的值小于先前的检索目的地处的值,则将这些值存储在寄存器中(S38,S40)。对所有检索目的地重复这些过程(S42)。

版权:(C)2008,日本特许厅&INPIT

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