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METHOD OF DIAGNOSING OBSTRUCTIVE IMPAIRMENT OF PATENCY OF AIRWAYS IN PATIENTS ON APPARATUS BREATHING

机译:诊断患者呼吸道阻塞性气管阻塞的方法

摘要

FIELD: medicine.;SUBSTANCE: invention can be used for patients who are on apparatus lung ventilation. For this purpose aerodynamic resistance of airways (Raw) is measured. First, proper aerodynamic resistance of airways (Raw proper) is calculated by formulas: Rawproper=250/(10h2+a+3), for patients from 0 to 30 years old, Rawproper=250/(10h2+a+3)+(a-30)/10, for patients over 30 years old, where: Rawproper  is proper aerodynamic resistance of airways, cm water column/l/s; h is patient's height, in metres; a is patient's age, in years, for patients under 1 year old "a" value is taken equal 1; 250, 10 and 3 are coefficients, specified on the basis of mathematical analysis. After that, aerodynamic resistance of airways (Raw) is measured with further calculation of ratio Raw proper/Raw. If value of ratio is higher than 0.8, absence of obstructive impairment is diagnosed. If value is from 0.8 to 0.5, 1 degree of obstructive impairment is diagnosed. If value of ratio is from 0.49 to 0.3, 2 degree of obstructive impairment is diagnosed. If value of ratio is from 0.29 and lower, 3 degree of obstructive impairment is diagnosed.;EFFECT: method ensures efficient diagnostics of obstructive impairment in said category of patients due to determination of relative value of aerodynamic resistance of airways (further - Raw) taking into account individual anthropometric parameters.;4 ex
机译:领域:药物;物质:本发明可用于正在进行器械肺通气的患者。为此,测量气道的空气动力学阻力(Raw)。首先,通过以下公式计算出适当的气道空气阻力(原始的):Raw proper = 250 /(10h 2 + a + 3) ,对于0至30岁的患者,Raw proper = 250 /(10h 2 + a + 3)+(a-30) / 10(对于30岁以上的患者),其中:Raw proper 是气道的适当空气动力学阻力,厘米水柱/升/秒; h是患者的身高,以米为单位; a是患者年龄,以岁为单位,对于1岁以下的患者,“ a”值等于1; 250、10和3是根据数学分析指定的系数。此后,通过进一步计算原始比/原始比来测量气道的空气动力学阻力(原始)。如果比率值大于0.8,则诊断为无阻塞障碍。如果值为0.8到0.5,则诊断为1度阻塞障碍。如果比率值从0.49到0.3,则诊断为2级阻塞性损害。如果该比率的值在0.29以下,则诊断为3度阻塞性损害。效果:由于确定了气道空气动力阻力的相对值(进一步-原始),该方法可确保对此类患者进行阻塞性损害的有效诊断考虑到各个人体测量学参数。; 4 ex

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