首页> 外国专利> HIGH-STRENGTH STEEL SHEET EXHIBITING EXCELLENT STRETCH-FLANGE FORMABILITY AND BENDING WORKABILITY, AND METHOD OF PRODUCING MOLTEN STEEL FOR THE HIGH-STRENGTH STEEL SHEET

HIGH-STRENGTH STEEL SHEET EXHIBITING EXCELLENT STRETCH-FLANGE FORMABILITY AND BENDING WORKABILITY, AND METHOD OF PRODUCING MOLTEN STEEL FOR THE HIGH-STRENGTH STEEL SHEET

机译:具有优异的拉伸-凸缘成形性和弯曲加工性的高强度钢板以及生产高强度钢板的熔融钢的方法

摘要

The present invention provides a high-strength steel sheet including: C: 0.03 to 0.25 mass %, Si: 0.1 to 2.0 mass %, Mn: 0.5 to 3.0 mass %, P: not more than 0.05 mass %, T.O: not more than 0.0050 mass %, S: 0.0001 to 0.01 mass %, N: 0.0005 to 0.01 mass %, acid-soluble Al: more than 0.01 mass %, Ca: 0.0005 to 0.0050 mass %, and a total of at least one element of Ce, La, Nd, and Pr: 0.001 to 0.01 mass %, with a balance including iron and inevitable impurities, in which the steel sheet contains a chemical component on a basis of mass that satisfies 0.7100×([Ce]+[La]+[Nd]+[Pr])/[acid-soluble Al]≦70 and 0.2≦([Ce]+[La]+[Nd]+[Pr])/[S]≦10, the steel sheet contains compound inclusion including a first inclusion phase containing at least one element of Ce, La, Nd, and Pr, containing Ca, and containing at least one element of O and S, and a second inclusion phase having a component different from that of the first inclusion phase and containing at least one element of Mn, Si, and Al, the compound inclusion forms a spherical compound inclusion having an equivalent circle diameter in the range of 0.5 μm to 5 μm, and a ratio of the number of the spherical compound inclusion relative to the number of all inclusions having the equivalent circle diameter in the range of 0.5 μm to 5 μm is 30% or more.
机译:本发明提供一种高强度钢板,其中,C:0.03〜0.25质量%,Si:0.1〜2.0质量%,Mn:0.5〜3.0质量%,P:0.05质量%以下,TO:0.05质量%以下。 0.0050质量%,S:0.0001〜0.01质量%,N:0.0005〜0.01质量%,酸溶性Al:0.01质量%以上,Ca:0.0005〜0.0050质量%,Ce中的至少一种元素合计, La,Nd,Pr:0.001〜0.01质量%,余量含有铁和不可避免的杂质,其中,钢板含有满足0.7 <100×([Ce] + [La]的质量的化学成分。 + [Nd] + [Pr])/ [酸溶性Al]≤70且0.2≤([Ce] + La + [Nd] + [Pr])/ [S]≤10,钢板中含有化合物夹杂物包括第一夹杂物相和第二夹杂物相,所述第一夹杂物相包含Ce,La,Nd和Pr的至少一种元素,所述元素包含Ca,并且含有O和S的至少一种元素;第二夹杂物相的成分不同于所述第一夹杂物相并且包含至少一种Mn,Si和Al元素d夹杂物形成等效圆直径在0.5μm至5μm范围内的球形化合物夹杂物,并且球形化合物夹杂物的数量相对于等效圆直径在0.5范围内的所有夹杂物的数量之比μm至5μm为30%以上。

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