NUMBER OF ELECTROMAGNETIC ENTITIES OF FLUX OF QUARKS, ENERGY OF ELECTROMAGNETIC ENTITIES, MOVEMENT OF ORBITS OF ELECTROMAGNETIC ENTITIES, AND STATUS IN PROTONS OF ELECTROMAGNETIC ENTITIES EJECTED FROM HIGH ENERGY ACCELERATOR

摘要

PROBLEM TO BE SOLVED: To reveal an original status, in protons, of a lot of electromagnetic entities ejected by collision between the protons in a high energy accelerator; and a principle of forming quarks.SOLUTION: The ejected electromagnetic entities were revolving in orbits of the electromagnetic entities in the protons. Suppose a proton includes a 1.7 MeV u quark, a 3.1 MeV u quark, and a 4.1 MeV d quark, then proton mass energy=(energy of electromagnetic entities in the proton)+1.7 MeV+3.1 MeV+4.1 MeV=938.272 MeV. The energy of the electromagnetic entities in the proton=938.272 MeV-8.9 MeV=929.372 MeV. From the energy of the ejected electromagnetic entities, the orbits of the electromagnetic entities can be calculated. The electromagnetic entities were revolving in the orbits of the electromagnetic entities. To determine how much the field of orbital energy of electromagnetic entities forming quarks is the orbital energy of (6.249×10)electromagnetic entities=1.233×10Jm×(6.249×10)pieces=1.233×10Jm×3.905×10pieces=4.815×10Jm. This is smaller than the orbital energy (8.665×10Jm) of the proton.SELECTED DRAWING: Figure 1