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首页> 外文期刊>Organometallics >Zirconium(IV) complexes having a rigid 1,8-naphthalene diamide versus a flexible 1,3-propylene diamide for olefin polymerization
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Zirconium(IV) complexes having a rigid 1,8-naphthalene diamide versus a flexible 1,3-propylene diamide for olefin polymerization

机译:具有刚性1,8-萘二酰胺和柔性1,3-丙烯二酰胺的锆(IV)络合物用于烯烃聚合

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Structure and chemical properties of zirconium(IV) complexes containing a rigid naphthalene diamide ligand ([1,8-C10H6(NSiMe3)(2)](2-)) or flexible propylene diamide ligands ([1,3-C3H6(NR)(2)](2-), R = SiMe3, Si(i-Pr)(3)) are described. The reaction of 1,8-C10H6(NHSiMe3)(2) with Zr(NMe2)(4) in refluxing toluene yields [1,8-C10H6(NSiMe3)(2)]Zr(NMe2)(2) (1), and the product 1 is converted to [1,8-C10H6(NSiMe3)(2)]ZrCl2 (2) in a moderate isolation yield by the treatment with excess ClSiMe3. X-ray crystallographic analysis establishes that 2 forms a dimer associated through two chloride bridges in the solid state and has a highly puckered six-membered ring with a small N-Zr-N bite angle (91.05 degrees). The reaction of 1,3-C3H6(NHR)(2) (R = SiMe3, Si(i-Pr)(3)) with Zr(NMe2)(4) also affords [1,3-C3H6(NR)(2)]Zr(NMe2)(2). Treatment of the amide complex with excess ClSiMe3 results in [1,3-C3H6(NR)(2)]ZrCl2 (4, R = SiMe3; 5, R Si(i-Pr)(3)) in a facile manner. The crystal structure of 5 shows that the molecule is monomeric, featuring a mirror plane that passes the zirconium atom and two chloride atoms, and the chelate and the metal form a boatlike six-membered ring with a large N-Zr-N angle (104.31 degrees). While these zirconium(IV) diamide complexes (2, 4, and 5) exhibit moderate ethylene polymerization activity (10-90 kg of PE/(mol(cat).atm.h)) in the presence of methylalumoxane, the diamide dimethyl compound [1,3-C3C6(NSi(i-Pr)(3))(2)]ZrMe2 (6) shows a high activity (300 kg of PE/(mol(cat).atm.h)) for the ethylene polymerization when it is activated with Ph3CB(C6F5)(4). [References: 37]
机译:含有刚性萘二酰胺配体([1,8-C10H6(NSiMe3)(2)](2-))或柔性丙烯二酰胺配体([1,3-C3H6(NR))的锆(IV)配合物的结构和化学性质(2)](2-),R = SiMe 3,Si(i-Pr)(3))被描述。 1,8-C10H6(NHSiMe3)(2)与Zr(NMe2)(4)在回流的甲苯中反应生成[1,8-C10H6(NSiMe3)(2)] Zr(NMe2)(2)(1),通过用过量的ClSiMe3处理,将产物1以中等的分离产率转化为[1,8-C10H6(NSiMe3)(2)] ZrCl2(2)。 X射线晶体学分析确定2形成通过固态的两个氯化物桥缔合的二聚体,并具有高度褶皱的六元环,且N-Zr-N咬合角较小(91.05度)。 1,3-C3H6(NHR)(2)(R = SiMe3,Si(i-Pr)(3))与Zr(NMe2)(4)的反应也提供[1,3-C3H6(NR)(2 )] Zr(NMe2)(2)。用过量的ClSiMe3处理酰胺络合物可轻松实现[1,3-C3H6(NR)(2)] ZrCl2(4,R = SiMe3; 5,R Si(i-Pr)(3))。 5的晶体结构表明该分子是单体的,具有穿过锆原子和两个氯原子的镜面,并且螯合物和金属形成了船形的六元环,具有大的N-Zr-N角(104.31度)。虽然这些二价锆(IV)二酰胺配合物(2、4和5)在甲基铝氧烷,二酰胺二甲基化合物的存在下表现出中等的乙烯聚合活性(10-90 kg PE /(mol(cat).atm.h)) [1,3-C3C6(NSi(i-Pr)(3))(2)] ZrMe2(6)对乙烯聚合显示出高活性(300 kg PE /(mol(cat).atm.h))当用Ph3CB(C6F5)(4)激活时。 [参考:37]

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