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A Simple Proof for the Inequality Between the Perron Root of a Nonnegative Matrix and that of Its Geometric Symmetrization

机译:非负矩阵的Perron根与其几何对称性不等式的简单证明

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摘要

Let A = (a_(ij)) be a nonnegative square matrix, let G = (g_(ij)) be its geometric sym metrization, i.e., (g_(i,j)=a_(ij)a_(ji))/(1/2), and let p denote the Perron root. We present a simple proof for the well-known inequality ρ(A) ≥ ρ(G).
机译:令A =(a_(ij))为非负方阵,令G =(g_(ij))为其几何对称性,即(g_(i,j)= a_(ij)a_(ji))/ (1/2),并令p代表Perron根。我们给出了众所周知的不等式ρ(A)≥ρ(G)的简单证明。

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