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首页> 外文期刊>Macromolecular Research >Synthesis and Characterization of New Poly(ester-imide)s Based on 1,3-bis(4,4'-bis(trimellitimido) phenyl)-2-propenone and Aromatic Diols
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Synthesis and Characterization of New Poly(ester-imide)s Based on 1,3-bis(4,4'-bis(trimellitimido) phenyl)-2-propenone and Aromatic Diols

机译:基于1,3-双(4,4'-双(三苯甲基亚氨基)苯基)-2-丙酮和芳族二元醇的新型聚酯酰亚胺的合成与表征

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摘要

Six new poly(ester-imide)s 9a-f were prepared by the rapid polycondensation reaction of 1,3-bis[4,4-bis(trimellitimidoyl chloride) phenyl]-2-propenone 7 with several aromatic diols 8a-f using a domestic microwave oven in the presence of a small amount of a polar organic medium, such as o-cresol. The polycondensation reaction proceeded more rapidly than solution polycondensation and was almost complete within 13 min, giving a series of poly(amide-imide)s in high yield with inherent viscosities ranging from 0.42 to 0.62 dL/g. All the above polymers were fully characterized by elemental analysis, viscosity measurements, solubility test, FTIR spectroscopy, differential scanning calorimetry (DSC) and thermal gravimetric analysis (TGA and DTG). 1,3-Bis [4,4'-bis(trimellitim-idoyl chloride) phenyl]-2-propenone 7 was synthesized by a four-step reaction. Initially, 4-nitro benzaldehyde 1 was reacted with 4-nitro acetophenone 2 in acetic anhydride to form 1,3-bis(4-nitro phenyl)-2-propenone 3. The dinitro 3 was then reduced to the diamine 4 using sodium sulfide. A condensation reaction of one equimolar of diamine 4 with two equimolars of trimellitic anhydride 5 in a mixture of acetic acid and pyridine (3:2) led to the formation of 1,3-bis[4,4-bis(trimelntimido) phenyl]-2-propenone 6. Finally the diacid 6 was converted to 1,3-bis[4,4'-bis(tri-mellitimidoyl chloride) phenyl]-2-propenone 7 by a reaction with thionyl chloride.
机译:通过1,3-双[4,4-双(三偏二甲酰氯)苯基] -2-丙烯酮7与几种芳族二醇8a-f的快速缩聚反应制备了六个新的聚(酯-酰亚胺)9a-f。在少量极性有机介质(例如邻甲酚)存在下的家用微波炉。缩聚反应比溶液缩聚反应进行得更快,并且在13分钟内几乎完成,从而以高收率得到一系列聚(酰胺-酰亚胺),固有粘度为0.42至0.62 dL / g。以上所有聚合物均通过元素分析,粘度测量,溶解度测试,FTIR光谱,差示扫描量热法(DSC)和热重分析(TGA和DTG)进行了全面表征。通过四步反应合成了1,3-双[4,4′-双(三苯甲基亚氨基氯酰)苯基] -2-丙烯酮7。首先,使4-硝基苯甲醛1与4-硝基苯乙酮2在乙酸酐中反应形成1,3-双(4-硝基苯基)-2-丙烯酮3。然后使用硫化钠将二硝基3还原为二胺4。 。在乙酸和吡啶(3:2)的混合物中,一个等摩尔的二胺4与两个等摩尔的偏苯三酸酐5的缩合反应导致形成1,3-双[4,4-双(trimelntimido)苯基] -2-丙烯酮6。最后,通过与亚硫酰氯反应,将二酸6转化为1,3-双[4,4'-双(三偏苯三酰氯)苯基] -2-丙烯酮7。

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