首页> 外文期刊>European journal of pharmaceutical sciences >Solution and solid state properties of a set of procaine and procainamide derivatives.
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Solution and solid state properties of a set of procaine and procainamide derivatives.

机译:一组普鲁卡因和普鲁卡因酰胺衍生物的溶液和固态性质。

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A set of potential Class III antiarrhythmic agents of structure p-HOOC-R-CO-NH-C(6)H(4)-CO-X-C(2)H(5)-N(C(2)H(5))(2) were isolated as crystalline solids of the amide and ester derivatives, I: succinylprocainamide (X=-NH-, R=-C(2)H(4)-); II: succinylprocaine (X=-O-, R=-C(2)H(4)-); III: maleylprocainamide (X=-NH-, R=-C(2)H(2)-) and IV: maleylprocaine (X=-O-, R=-C(2)H(2)-). Although compounds I-IV exhibit similar solution properties (i.e. acid-base speciation, with zwitterionic (+-) to neutral (00) form ratios higher than 10(4)), aqueous solubility of -NH- derivatives is significantly higher than that of -O- derivatives and also, solvent effects on solubility (i.e. the change of water by ethanol) is clearly different in both series. Solution and solid-state properties of I-IV were characterized to account for the observed differences. Results indicate that procainamide derivatives I and III crystallizes as (+-)(s) but procaine derivatives II and IV as (00)(s). Besides, I is anhydrous but II-IV are hydrates. Aqueous solubility and solvent effect on solubility are controlled by the intrinsic solubility of the species (+-) in I and III and (00) in II and IV. The rise of hydrophilicity of species (00) due to the structural change from -O- to -NH- would determine the change in the structure of the precipitating crystals from (00)(s) to (+-)(s). Solid structure (zwitterionic or neutral), as well as composition (anhydrous or hydrated) may be recognized as the main factors in determining the rank of aqueous solubility of the set: (+-)>(+-.H(2)O)>(00.H(2)O).
机译:一组结构p-HOOC-R-CO-NH-C(6)H(4)-CO-XC(2)H(5)-N(C(2)H(5)的潜在III类抗心律不齐药物)(2)分离为酰胺和酯衍生物的结晶固体,I:琥珀酰普鲁卡因酰胺(X = -NH-,R = -C(2)H(4)-); II:琥珀酰基普鲁卡因(X = -O-,R = -C(2)H(4)-); III:马来基普鲁卡因酰胺(X = -NH-,R = -C(2)H(2)-)和IV:马来基普鲁卡因(X = -O-,R = -C(2)H(2)-)。尽管化合物I-IV表现出相似的溶液性质(即酸碱形态,两性离子(+-)与中性(00)的比率高于10(4)),但-NH-衍生物的水溶性明显高于-O-衍生物以及溶剂对溶解度的影响(即乙醇对水的变化)在两个系列中都明显不同。对I-IV的溶液和固态性质进行表征以解决观察到的差异。结果表明普鲁卡因酰胺衍生物I和III结晶为(+),而普鲁卡因衍生物II和IV结晶为(00)。此外,I是无水的,但是II-IV是水合物。水溶液的溶解度和溶剂对溶解度的影响由物种(+-)在I和III中以及(00)在II和IV中的固有溶解度控制。由于从-O-到-NH-的结构变化,物质(00)的亲水性上升将决定沉淀晶体从(00)到(+)的晶体结构的变化。固体结构(两性离子或中性)以及组成(无水或水合)可以被视为确定该组水溶性的等级的主要因素:(+-)>(+-。H(2)O) >(00.H(2)O)。

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