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Revisiting 'Quantum State Sharing of an Arbitrary Two-Atom State by Using a Six-Atom Cluster State in Cavity QED'

机译:重新讨论“通过在腔体QED中使用六原子簇状态来共享任意两原子状态的量子状态”

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摘要

In Nie et al. (Int. J. Theor. Phys. 50: 2526, 2011), authors put forward a cavity QED scheme for deterministic quantum state sharing (QSTS) of an arbitrary two-atom state. They claimed that, the quantum channel of the QSTS scheme is a six-atom cluster state. After simple calculation, one can see that the quantum channel they used is a direct product of two three-atom GHZ states. In this paper, we propose a cavity QED scheme for QSTS of an arbitrary two-atom state via a six-atom cluster state channel. In our scheme, two two-atom Bell state measurements are transformed into the discrimination of single-atom product states. Moreover, the two-atom unitary operation is changed to single-qubit unitary operations. Our scheme is insensitive to the cavity decay. The necessary time for the scheme is much shorter than the Rydberg-atom lifespan, therefore atom decays do not need to be considered.
机译:在聂等人。 (Int。J. Theor。Phys。50:2526,2011),作者提出了腔QED方案,用于任意两个原子态的确定性量子态共享(QSTS)。他们声称,QSTS方案的量子通道是六原子簇状态。通过简单的计算,可以看到它们使用的量子通道是两个三原子GHZ状态的直接乘积。在本文中,我们提出了一种通过六原子簇状态通道对任意两个原子状态的QSTS进行腔QED的方案。在我们的方案中,将两个两个原子的贝尔状态测量结果转换为对单个原子产物状态的判别。此外,将两个原子的单一运算更改为单量子位单一运算。我们的方案对腔衰变不敏感。该方案所需的时间比里德伯格原子的寿命短得多,因此不需要考虑原子衰变。

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