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Twelve-quark hypernuclei with A=4 in a relativistic quark-gluon model

机译:相对论夸克胶子模型中A = 4的十二夸克超核

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摘要

Hypernuclei He-4(Y), H-4(Y), He-4(YY), H-4(YY), where Y = Lambda, Sigma(0), Sigma(+), Sigma(-), with the atomic (baryon) number A = B = 4, are described by the relativistic twelve-quark equations in the framework of the dispersion relation technique. Hypernuclei as the systems of interacting quarks and gluons are considered. The relativistic twelve-quark amplitudes of hypernuclei, including the constituent quarks of three flavors u, d, s are calculated. The approximate solutions of these equations are obtained using a method based on extraction of leading singularities of the amplitudes. The poles of the multiquark amplitudes allow us to determine the masses and the binding energy of hypernuclei with A = 4. The mass and the binding energy of state H-4(Lambda Lambda) with the isospin projection I-3 = 0 and the spin-parity J(P) = 0(+) is equal to M = 4118 MeV and B = -8 MeV, respectively. We predict the mass spectrum of hypernuclei with A = 4, which is valuable for further experimental study of the hypernuclei.
机译:超核He-4(Y),H-4(Y),He-4(YY),H-4(YY),其中Y = Lambda,Sigma(0),Sigma(+),Sigma(-),原子(重子)数A = B = 4,由色散关系技术框架中的相对论十二夸克方程描述。超核是与夸克和胶子相互作用的系统。计算了超核的相对论十二夸克振幅,包括三个风味u,d,s的构成夸克。这些方程的近似解是使用基于幅度前导奇点提取的方法获得的。多重夸克振幅的极点使我们能够确定A = 4的超核的质量和结合能。等旋投影I-3 = 0且自旋的状态H-4(Lambda Lambda)的质量和结合能-parity J(P)= 0(+)分别等于M = 4118 MeV和B = -8 MeV。我们预测超核的质谱为A = 4,这对于进一步研究超核具有重要的价值。

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