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Long paths in hypercubes with conditional node-faults

机译:具有条件节点故障的超立方体中的长路径

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Let F be a set of f <= 2n - 5 faulty nodes in an n-cube Q(n) such that every node of Q(n) still has at least two fault-free neighbors. Then we show that Q(n) - F contains a path of length at least 2(n) - 2f - 1 (respectively, 2(n) - 2f - 2) between any two nodes of odd (respectively, even) distance. Since the n-cube is bipartite, the path of length 2(n) - 2f - 1 (or 2(n) - 2f - 2) turns out to be the longest if all faulty nodes belong to the same partite set. As a contribution, our study improves upon the previous result presented by [J.-S. Fu, Longest fault-free paths in hypercubes with vertex faults, Information Sciences 176 (2006) 759-771] where only n - 2 faulty nodes are considered. (c) 2008 Elsevier Inc. All rights reserved.
机译:令F为n立方体Q(n)中的f <= 2n-5个故障节点的集合,这样Q(n)的每个节点仍至少具有两个无故障的邻居。然后我们证明Q(n)-F在奇数(分别为偶数)距离的任意两个节点之间包含的路径长度至少为2(n)-2f-1(分别为2(n)-2f-2)。由于n立方体是二分体,因此如果所有故障节点都属于同一分体集,则长度为2(n)-2f-1(或2(n)-2f-2)的路径最长。作为贡献,我们的研究对[J.-S. Fu,具有顶点故障的超立方体中的最长无故障路径,Information Sciences 176(2006)759-771],其中仅考虑n-2个故障节点。 (c)2008 Elsevier Inc.保留所有权利。

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